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Liono4ka [1.6K]

3 years ago

5

There are 70 sixth graders at Wilson Middle School. Only 40% of the sixth graders will attend the morning assembly. How many six

th graders will be at the morning assembly?

1 answer:

love history [14]3 years ago

8 0

Answer: 42

Step-by-step explanation:

We know that because 40% percent of 70 equals 28. So we do the following-

70 minus 28 equals 42!

Glad to help!

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melamori03 [73]

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3 years ago

5x/-6 + 9/ -6 = 3x/-3 + 6/ -3 step by step

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2 years ago

To divide 1.89 ÷ 0.9, we need to change it. Choose the correct problem below to show what the “new” look would be.

Arlecino [84]

Answer:

D. 18.9 ÷ 9

Step-by-step explanation:

we need to divide

1.89 ÷ 0.9 but write it in different form

so ,we need to eliminate decimal from 0.9

as 0.9*10 = 9

thus,we multiply both 1.89 and 0.9 with 10, then we will have

(1.89*10) ÷ (0.9*10)

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8 0

3 years ago

Help please thank you

Tanya [424]

Answer:

the answer is 0.15

Step-by-step explanation:

you cound 0.10 + 0.04 + 0.01 and then you have 0.15

3 0

3 years ago

Read 2 more answers

The national average for the math portion of the College Board’s Scholastic Aptitude Test

Alex73 [517]

Answer:

a) 0.1587

b) 0.023

c) 0.341

d) 0.818

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 515

Standard Deviation, σ = 100

We are given that the distribution of SAT score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(score greater than 615)

P(x > 615)

$P( x > 615) = P( z > \displaystyle\frac{615 - 515}{100}) = P(z > 1)$

$= 1 - P(z \leq 1)$

Calculation the value from standard normal z table, we have,

$P(x > 615) = 1 - 0.8413 = 0.1587 = 15.87\%$

b) b) P(score greater than 715)

$P(x > 715) = P(z > \displaystyle\frac{715-515}{100}) = P(z > 2)\\\\P( z > 2) = 1 - P(z \leq 2)$

Calculating the value from the standard normal table we have,

$1 - 0.977 = 0.023 = 2.3\%\\P( x > 715) = 2.3\%$

c) P(score between 415 and 515)

$P(415 \leq x \leq 515) = P(\displaystyle\frac{415 - 515}{100} \leq z \leq \displaystyle\frac{515-515}{100}) = P(-1 \leq z \leq 0)\\\\= P(z \leq 0) - P(z < -1)\\= 0.500 - 0.159 = 0.341 = 34.1\%$

$P(415 \leq x \leq 515) = 34.1\%$

d) P(score between 315 and 615)

$P(315 \leq x \leq 615) = P(\displaystyle\frac{315 - 515}{100} \leq z \leq \displaystyle\frac{615-515}{100}) = P(-2 \leq z \leq 1)\\\\= P(z \leq 1) - P(z < -2)\\= 0.841 - 0.023 = 0.818 = 81.8\%$

$P(315 \leq x \leq 615) = 81.8\%$

4 0

3 years ago