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3 years ago

Pls halp im bad at math

Mathematics

1 answer:

Nostrana [21]3 years ago

4 0

Answer:

what do you need help in

Step-by-step explanation:

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(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

8 0

3 years ago

A given line has the equation 10x+2y=-2.

Iteru [2.4K]

The equation of a line of the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

If two lines are parallel then their slopes are equal.

We have the following line:

$10x + 2y = -2\\2y = -10x-2\\y = -5x-1$

Thus, the slope of the line is -5.

Therefore a parallel line is of the form:

$y = -5x + b$

We replace the point $(0,12)$

$12 = -5 (0) + b\\12 = b$

Finally, the equation is of the form:

$y = -5x + 12$

Answer:

$5x + y = 12$

8 0

4 years ago

14 fr to 21 ft ( simply )

zimovet [89]

If you're asking the difference between 14 ft and 21 ft your answer is 7 ft, just subtract 14 from 21

6 0

3 years ago

Can a smart brainstormer help me

lukranit [14]

The answer is .1391
Hope this helps!
(If your confused, I just put this in a calculator)

3 0

3 years ago

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What is the image point of (-1, -7) after a translation left 3 units and up 2 units?

3241004551 [841]

Answer:

(-4,-5)

Step-by-step explanation:

3 0

3 years ago

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