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Tamiku [17]
3 years ago
14

A toy manufacturer is shipping its newest product, an interactive talking globe, to a major toy store. The packaging for the glo

be is a rectangular prism that measures 2512 2512 inches high, 18 inches long, and 18 inches wide. The boxes for the globes are packaged into shipping crates that hold 8 globes each. What is the minimum volume of one shipping crate? Explain your answer in the space provided.
Mathematics
1 answer:
Afina-wow [57]3 years ago
5 0

Answer:

6 511 104 in³

Step-by-step explanation:

Since we have 1 crate and 8 boxes fit into one crate.

So, volume of one crate, V' = 8 × volume of 1 box, V

Since the box is a rectangular prism of sides 2512 inches high, 18 inches long, and 18 inches wide, its volume, V = lwh where l = length of prism, h = height of prism and w = width of prism.

So, V = lwh = 18 in × 18 in × 2512 in = 813 888 in³

So, V' = 8 × 813 888 in³ = 6 511 104 in³

So, the minimum volume of the crate is 6 511 104 in³

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In parallelogram ABCD, AB = 16 cm, DA = 3<img src="https://tex.z-dn.net/?f=%5Csqrt%7B2%7D" id="TexFormula1" title="\sqrt{2}" alt
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Answer:

length of segment YZ is 8 cm

Step-by-step explanation:

given data

AB = 16 cm

DA = 3\sqrt{2} cm

AB and DA form interior angle  =  45-degre

WX ≠ YZ

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to find out

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solution

area of △ABD is  the same as the area of △BCD

and

area of △ABD is express as

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area of the parallelogram = 48

so

now we will consider here YZ = x

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WM = ZM = (16 - x)  ÷ 2   .......................2

so area of  trapezoid will be

area of  trapezoid = \frac{ZY + WX }{2}  \times ZM         .......................3

area of  trapezoid = \frac{x+16}{2} \times \frac{16 - x}{2}    

48 = \frac{x+16}{2} \times \frac{16 - x}{2}  

solve it we get

x = 8

so length of segment YZ is 8 cm

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