29). The 'six' is the same as (6 x 5) = 30 fifths.
So six and three fifths = (30 + 3) fifths = thirty-three fifths.
30). The 'eight' is the same as (8 x 6) = 48 sixths.
So eight and five sixths = (48 + 5) fifths= fifty-three sixths.
31). Twenty-seven of the thirds are the same as (27/9) = 3 .
That leaves a remainder of 2 thirds.
So twenty-nine thirds are the same as 3 and 2/3 .
32). Thirty-two of the fourths are the same as (32/4) = 8 .
That leaves a remainder of one fourth.
So thirty-three fourths are the same as 4 and 1/4 .
Answer:
32
hope this helps
have a good day :)
Step-by-step explanation:
Answer:
x = 24
Step-by-step explanation:
using the rule of exponents
× 
= 
consider left side
× 
= × 
= 
then
= 
since the bases on both sides are equal, both 5 then equate exponents
= 16 ( multiply both sides by 6 )
4x = 96 ( divide both sides by 4 )
x = 24
Answer:
~1.8 mile
Step-by-step explanation:
Michael lives at the closest point to the school (the origin) on Maple Street, which can be represented by the line y = 2x – 4.
This means Michael's house will be the intersection point of line y1 (y = 2x - 4) and line y2 that is perpendicular to y1 and passes the origin.
Denote equation of y2 is y = ax + b,
with a is equal to negative reciprocal of 2 => a = -1/2
y2 pass the origin (0, 0) => b = 0
=> Equation of y2:
y = (-1/2)x
To find location of Michael's house, we get y1 = y2 or:
2x - 4 = (-1/2)x
<=> 4x - 8 = -x
<=> 5x = 8
<=> x = 8/5
=> y = (-1/2)x = (-1/2)(8/5) = -4/5
=> Location of Michael' house: (x, y) = (8/5, -4/5)
Distance from Michael's house to school is:
D = sqrt(x^2 + y^2) = sqrt[(8/5)^2 + (-4/5)^2) = ~1.8 (mile)
