Send a better photo or tell me what I’m suppose to be answering
(6 + 5x)(7x + 3) = 42x + 18 + 35x^2 + 15x = 35x^2 + 57x + 18
Answer:
We have to prove
sin(α+β)-sin(α-β)=2 cos α sin β
We will take the left hand side to prove it equal to right hand side
So,
=sin(α+β)-sin(α-β) Eqn 1
We will use the following identities:
sin(α+β)=sin α cos β+cos α sin β
and
sin(α-β)=sin α cos β-cos α sin β
Putting the identities in eqn 1
=sin(α+β)-sin(α-β)
=[ sin α cos β+cos α sin β ]-[sin α cos β-cos α sin β ]
=sin α cos β+cos α sin β- sinα cos β+cos α sin β
sinα cosβ will be cancelled.
=cos α sin β+ cos α sin β
=2 cos α sin β
Hence,
sin(α+β)-sin(α-β)=2 cos α sin β
I don't know how to solve this but im pretty sure the table is needed so you should atleast take a picture or just type it out
Answer:
Step-by-step explanation:
The picture of the question in the attached figure
we know that
The measurement of the external angle is the half-difference of the arches that comprise
so
Remember that the sum of the major arc and a minor arc is equal to 360 degrees
we have
----> is given
so
substitute the values
