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2 years ago

Which shot is used to put the tennis ball in play or the birdie for badminton in play?

Mathematics

1 answer:

BartSMP [9]2 years ago

4 0

Serve cause no one is supposed to even touch the ball till it is served.

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Given the figure below determine the value of x and y

guajiro [1.7K]

sry, the figure hasn't been attached

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2 years ago

Which equation represents a circle with a center at (-4,9) and a diameter of 10 units?

Dennis_Churaev [7]

Answer:

$(x+4)^2 + (y-9)^2 = 25$

Step-by-step explanation:

To write the equation of a circle, use the formula $(x-h)^2+(y-k)^2 = r^2$ where the center of the circle is (h, k).

This means the equation is $(x--4)^2 + (y-9)^2 = r^2\\\(x+4)^2 + (y-9)^2 = r^2$ .

Find the radius r by dividing the diameter of 10 in 2. The radius is 5.

So the equation of the circle is $(x+4)^2 + (y-9)^2 = 25$

7 0

3 years ago

What is the answer to 3/5q=1

elena-14-01-66 [18.8K]

3/5q = 1 Given

(3/5) 3/5q = 1(3/5) Multiply each side by 3/5 (Mult. Prop. of Equal)

q = 3/5 Simplify

6 0

3 years ago

Read 2 more answers

218 rounded to nearest 10

tangare [24]

The answer is 220 because you would just have to round 1 to 2 than everytging behind it is a zero

4 0

3 years ago

Read 2 more answers

Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-

djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

$A(x_{1}, y_{1}})=(-20, 25)$

$B(x_{2}, y_{2}})=(30, 25)$

$C(x_{3}, y_{3}})=(30, -10)$

$D(x_{4}, y_{4}})=(-20, -10)$

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

$d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ ----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

$AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}$

$AB=\sqrt{(30+20)^{2}}$

$AB=\sqrt{(50)^{2}$

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

$d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}$

$BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}$

$BC=\sqrt{(-35)^{2}}$

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

$d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}$

$DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}$

$DC=\sqrt{(30+20)^{2}}$

$DC=\sqrt{(50)^{2}}$

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

$d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}$

$AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}$

$AD=\sqrt{(-20+20)^{2}+(-35)^{2}}$

$AD=\sqrt{(-35)^{2}}$

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0

3 years ago