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3 years ago

I giveeeeeeeeeeeeeeeee brainlilstttttt

Mathematics

2 answers:

Aleks04 [339]3 years ago

8 0

Answer:

It's the first one

Step-by-step explanation: give me brainlist LOL

Lyrx [107]3 years ago

6 0

Answer:

I think the answer is b or c

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The radius of a semicircle is 1 kilometer. what is the semicircle's perimeter? use 3.14 for pie.

Aleksandr-060686 [28]

Answer:

5.14 km

Step-by-step explanation:

A semicircle is 1/2 of a circle so the perimeter is just 1/2 of the circumference

C = 2 * pi r for a circle so for a semicircle

1/2* 2* pi *r

pi*r

3.14 * 1

3.14

If we want to include the piece that closes the semicircle, we need to add the diameter

d = 2r = 2(1) = 2

2+3.14 = 5.14

5 0

3 years ago

OH GOD PLEASE HELP ME MY BRAIN HURTS!

alukav5142 [94]

Your answer should be 71. :)

8 0

3 years ago

A rabbit population doubles every 4 weeks.There are currently five rabbits in a restricted area. If t represents the time in wee

sertanlavr [38]

Doubling formula is this:

$P(t)=P(2)^{\frac{t}{d}}$
where P=initial number of rabbits
t=time
d=time it takes to doulbe

ok, so 4 weeks is the doubling time so that is 4*7=28 days

we wawnt time=98
and oroiginal number of rabbits is 5 so
$P(98)=5(2)^{\frac{98}{28}}$
$P(98)=5(2)^{3.5}$
$P(98)=5(2^3)(\sqrt{2})$
$P(98)=5(8)\sqrt{2}$
$P(98)=40\sqrt{2}$
so P(98)≈56.56
we can't have .56 rabbit so round down or up
about 56 or 57 rabbits in 98 days

8 0

3 years ago

Pleaseeee help meeeeeee

Rasek [7]

I think it's the first one :?

5 0

3 years ago

Simplify

OlgaM077 [116]

Answer:

see below

Step-by-step explanation:

$\frac{x-1}{x^2-3x+2}+ \frac{x-2}{x^2-5x+6} +\frac{x-5}{x^2-8x+15}$

we need to simplify that

$x^2-3x+2=(x-1)(x-2)\\\\x^2-5x+6=(x-2)(x-3)\\\\x^2-8x+15=(x-3)(x-5)$

so we can continue

$\frac{x-1}{(x-1)(x-2)}=\frac{1}{x-2}\\\\\frac{x-2}{(x-2)(x-3)} =\frac{1}{x-3}\\\\\frac{x-5}{(x-3)(x-5)} =\frac{1}{x-3}$

and we can put all together

$\frac{1}{x-2}+ \frac{1}{x-3}+ \frac{1}{x-3}\\\\\frac{1}{x-2} +\frac{2}{x-3}\\\\\frac{x-3}{(x-3)(x-2)}+ \frac{2(x-2)}{(x-2)(x-3)} \\\\\frac{x-3+2x-4}{(x-3)(x-2)}\\\\\frac{3x-7}{x^2-5x+6}$

3 0

3 years ago