Where’s the photo to this question?
Answer:
Step-by-step explanation:
Part A
2x-3y =21 in slope-intercept form is y=2/3x-7 one you graph the equation it would be a parallel to the equation shown above so there are no intersections
PART B
y=1/3x^2 and y= 2/3x - 5
1/3x^2 = 2/3x-5
1/3x^2=2/3x-5
then u multiply everything by 3
1/3x^2*3 =2/3x *3-5*3
the three for 1/3*3 cancels out so you are left with
1x^2= 2x -15
1x^2-2x+15=0
You can not factor it and well i guess there is no intersection
im sorry if i got this wrong bc i had a similar question just different numbers and i tried to solve this one the way i sloved mine so im not sure of my answer for part b
Let the first number = x
The second number would be x +1
3rd number = x +2
4th number = x +3
5th number = x+4
6th number = x+5
7th number = x +6
8th number = x +7
9th number = x+8
The sum is 279
Combine like terms in the 9 numbers to get: 9x + 36 = 279
Solve for x:
9x + 36 = 279
Subtract 36 from both sides:
9x = 243
Divide both sides by 9:
x =27
The first number is 27
The last number would be 27 + 8 = 35
The sum of the first and last would be 27 + 35 = 63
Answer:
j1= -9 j2= 9
Step-by-step explanation:
