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lina2011 [118]
3 years ago
7

At noon, ship A is 150 km west of ship B. Ship A is sailing east at 35 km/h and ship B is sailing north at 30 km/h. How fast is

the distance between the ships changing at 4:00 PM?
Mathematics
1 answer:
Marrrta [24]3 years ago
4 0

Answer:

150 km/h

Step-by-step explanation:

because it's then 2 together

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The answer would be 25 because all of the others are prime numbers, meaning they can only be divided by themselves and 1. So it would be C.
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Giving brainliest to the answer who gives step by step examples clearly!
Anarel [89]

<em>Hi there!</em>

<em>This should be easy,lol!</em>

<em>Answer:</em>

<em />\sqrt[3]{-128} = \boxed{-128 \sqrt{3} }<em> (Decimal: -221.702503)</em>

<em />\sqrt[3]{162} = \boxed{162 \sqrt{3} }<em> (Decimal: 280.592231)</em>

<em />\sqrt[3]{-1000x^4} = \boxed{-1732.050808x^4}<em />

<em>Sorry bout the explanation thingy. Their really long -.-!</em>

<em>But the last one is short so i'll put it for you!</em>

<em>Step-by-step explanation:</em>

<em>∴!For the last one!∴</em>

<em />\sqrt[3]{-1000x^4}<em />

<em>Simplifies to:</em>

<em />= - 1732.050808 * x^4<em />

<em />= - 1732.050808 * ( x * x * x * x)<em> </em>

<em />= - 1732.050808x^4<em />

<em>Have a great day/night!</em>

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