[ - 6 * x^2 * y^8 + 12* x * y^3 - 36 * x * y^2 ] / [6*x*y^2] =
[-6x^2 y^8 ] / [6xy^2] + [12x y^3] / [6xy^2] - [36xy^2] / [6xy^2] =
- xy^6 + 2y - 6
Answer: - xy^6 + 2y - 6
Answer: The critical value for a two-tailed t-test = 2.056
The critical value for a one-tailed t-test = 1.706
Step-by-step explanation:
Given : Degree of freedom : df= 26
Significance level :
Using student's t distribution table , the critical value for a two-tailed t-test will be :-
The critical value for a two-tailed t-test = 2.056
Again, Using student's t distribution table , the critical value for a one-tailed t-test will be :-
The critical value for a one-tailed t-test = 1.706
Answer:
60 lbs left over
Step-by-step explanation: Since the small containers hold 8 lbs each you multiply 8 by 2 since there are 2 containers. Same for the large, multiply 9 by 12 because each container holds 12 lbs and there is 9 containers. Then, you subtract 4 from that total because she already used 4 lbs.
x=(2*8)+(9*12)-4 Multiply
x=16+108-4 Simplify
x=120
So, before she fills the bird feeders she has 120 lbs of bird seed. There are 30 bird feeders and since they hold 2 lbs each you multiply 30 and 2. Then you subtract that from the 120 lbs because she is filling the bird feeders with that seed.
120- (30*2)
120-60= 60 lbs left over
The entire yard is 36x54 so you would draw a rectangle with those measurements, since there is a border of 3 you should draw another rectangle in the middle with measurements 6 less than the original. 30x48
since you are finding the area of the walk, you would find the larger area, then subtract the smaller rectangle
(36*54)-(30*48)
1944-1440
504 square feet of walk