To find the volume of a box that would hold these nine cylinders, you would start with the formula for volume of a cylinder. V=pi x r^2 x h. Substitute in the known volume and the known Height. 9.425=pi x r^2 x 3. Divide both sides by three to get approximately 3.143 = pi x r^2. Divided by pi on both sides. This leaves you with one = r^2. So the radius is equal to one. If the radius equals one, the diameter is two. Assuming the cylinders are arranged in a 3 x 3 array, the length and width of the rectangle or box would be 6cm x 6cm. To find the volume of the box necessary, multiply the length of six by the width of six by the height of three. The volume would be 108 square cm.
The answer should be true
Answer:
-2, -2/1
Step-by-step explanation:
If you start from the point in the quadrant II, you go 1 to the right and 2 down and there will be another point on the line. For example, from point (-3, 6) when you go 1 right and 2 down the next point is (-2, 4).
Cross multiply and divide
Put 191 over 238 (like a fraction) the put another fraction bar right next to your first fraction and put 100 on bottom (this equals a whole in % and it's right across from the total of 238 free throws) then multiply 191 by 100 then divide by 238 and that answer should be your the percent you need.
Answer:
Yes
Step-by-step explanation:
The answer is proportional because the variables correspond directly to each other.
1=225
2=450
3=675
4=900
