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GalinKa [24]
3 years ago
15

The perimeter of a regular hexagon is 78 cm .What will be the length of each side?

Mathematics
2 answers:
k0ka [10]3 years ago
7 0

Answer:

13 cm

Step-by-step explanation:

78/6=13

ipn [44]3 years ago
5 0

Answer:

13cm

Step-by-step explanation:

  • regular means the sides are equal
  • a hexagon has 6sides
  • 78/6=13
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(HELP ASAP!!) An exterior angle of a triangle is 152°. If the non-adjacent angles are congruent, then what are the measures of a
tresset_1 [31]

Answer:

  c) 28°, 76°, 76°

Step-by-step explanation:

The two remote interior angles sum to 152°. Since they are congruent, their measures are 152°/2 = 76°. The adjacent interior angle is the supplement of 152°, so is 180°-152° = 28°.

The interior angles are 28°, 76°, 76°.  . . . .  matches choice C

4 0
3 years ago
A bicycle has a listed price of 
Yakvenalex [24]

Answer: 57.9 dollar

891.95 x 6.5%

4 0
4 years ago
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A bacteria culture starts with 400 bacteria and grows at a rate proportional to its size. After 4 hours, there are 9000 bacteria
Kaylis [27]

Answer:

A) The expression for the number of bacteria is P(t) = 400e^{0.7783t}.

B) After 5 hours there will be 19593 bacteria.

C) After 5.55 hours the population of bacteria will reach 30000.

Step-by-step explanation:

A) Here we have a problem with differential equations. Recall that we can interpret the rate of change of a magnitude as its derivative. So, as the rate change proportionally to the size of the population, we have

P' = kP

where P stands for the population of bacteria.

Writing P' as \frac{dP}{dt}, we get

\frac{dP}{dt} = kP.

Notice that this is a separable equation, so

\frac{dP}{P} = kdt.

Then, integrating in both sides of the equality:

\int\frac{dP}{P} = \int kdt.

We have,

\ln P = kt+C.

Now, taking exponential

P(t) = Ce^{kt}.

The next step is to find the value for the constant C. We do this using the initial condition P(0)=400. Recall that this is the initial population of bacteria. So,

400 = P(0) = Ce^{k0}=C.

Hence, the expression becomes

P(t) = 400e^{kt}.

Now, we find the value for k. We are going to use that P(4)=9000. Notice that

9000 = 400e^{k4}.

Then,

\frac{90}{4} = e^{4k}.

Taking logarithm

\ln\frac{90}{4} = 4k, so \frac{1}{4}\ln\frac{90}{4} = k.

So, k=0.7783788273, and approximating to the fourth decimal place we can take k=0.7783. Hence,

P(t) = 400e^{0.7783t}.

B) To find the number of bacteria after 5 hours, we only need to evaluate the expression we have obtained in the previous exercise:

P(5) =400e^{0.7783*5} = 19593.723 \approx 19593.  

C) In this case we want to do the reverse operation: we want to find the value of t such that

30000 = 400e^{0.7783t}.

This expression is equivalent to

75 = e^{0.7783t}.

Now, taking logarithm we have

\ln 75 = 0.7783t.

Finally,

t = \frac{\ln 75}{0.7783} \approx 5.55.

So, after 5.55 hours the population of bacteria will reach 30000.

6 0
3 years ago
Simplify (7x−13)−(x+5)
igor_vitrenko [27]
Greetings!

Simplify.
(7x-13)-(x+5)
Distribute the Parenthesis.
7x-13-x-5
Combine Like Terms.
7x-x-13-5
6x-18

Hope this helps.
-Benjamin
5 0
3 years ago
Read 2 more answers
What is the logarithmic form of 9² = 81?
Scorpion4ik [409]

Answer:

9*9=81

(if it is wrong i am sorry!)

8 0
3 years ago
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