<span>Find the wind speed and the plane's airspeed.
:
Let s = speed of the plane in still air
Let w = speed of the wind
then
(s-w) = plane speed against the wind
and
(s+w) = plane speed with the wind
:
Change 3 3/8 hrs to 3.375 hrs
:
The trips there and back are equal distance, (1890 mi) write two distance equations
dist = time * speed
:
3.375(s-w) = 1890
3.0(s + w) = 1890
:
It is convenient that we can simplify both these equations:
divide the 1st by 3.375
divide the 2nd by 3
resulting in two simple equations that can be used for elimination of w
s - w = 560
s + w = 630
----------------adding eliminates w, find s
2s = 1190
s =
s = 595 mph is the plane speed in still air
Find w
595 + w = 630
w = 630 - 595
w = 35 mph is the wind spee</span>
Answer:

Step-by-step explanation:
We know that f(-2)=7
x+4 = -2 <=> x = -6
so f(-6+4) = f(-2)=7
then the corresponding point is (-6,7)
Step-by-step explanation:
You should prolly subtract 2 from both sides first.
So you get, -|2/5x + 3| > -1 2/5
- Add three to both sides
- -|2/5x| = -1 2/5
- Do -1 and 2/5 divided by 2/5 to get -3.5, x > -3.5
One of the answers is x > -3.5 but you need to switch the sign to less than and make the other side the opposite.

You see that, switched the sign and made whats on the right side opposite. So now solve for x again but with this new equation. Also, the parentheses are absolute value signs
Subtract 3 from both sides
-|2/5x| < -1 and 3/5
Divide 2/5 from each side to get x < -4
I hope I'm correct, my bad if I'm wrong
4×11+1=45
A+B+C=180 60+75+C=180 180_130=c c=45