Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even.
m=2k-n, p=2l-n
Let m+n and n+p be even integers, thus m+n=2k and n+p=2l by definition of even
m+p= 2k-n + 2l-n substitution
= 2k+2l-2n
=2 (k+l-n)
=2x, where x=k+l-n ∈Z (integers)
Hence, m+p is even by direct proof.
Answer:
x = 13
Step-by-step explanation:
Given
x + 15 = 28
Isolate x on the left side by subtracting 15 from both sides
x = 28 - 15 = 13
(-9/2)/(7/5)
= (-9/2)*(5/7)
= -45/14
= -3 3/14
The final answer is -3 3/14~
Answer:
A. -205.7 kJ
Step-by-step explanation:
The overall enthalpy of reaction be calculated when the intermediate steps are present
formed in a multi-step process.
