If f(x) = 2x - 5 and g(x) = x + 52, then f(g(x)) can be deduced by placing g(x) in the spot of x in the f(x) equation as follows:
f(g(x)) = 2(g(x)) - 5
Since we know g(x) = x + 52, let's plug it in:
f(g(x)) = 2(x + 52) - 5
f(g(x)) = 2x + 104 - 5
f(g(x)) = 2x + 99
Answer:
h = 10sin(π15t)+35
Step-by-step explanation:
The height of the blade as a function f time can be written in the following way:
h = Asin(xt) + B, where:
B represets the initial height of the blade above the ground.
A represents the amplitud of length of the blade.
x represents the period.
The initial height is 35 ft, therefore, B = 35ft.
The amplotud of lenth of the blade is 10ft, therefore A = 10.
The period is two rotations every minute, therefore the period should be 60/4 = 15. Then x = 15π
Finally the equation that can be used to model h is:
h = 10sin(π15t)+35
The simplified expression for the given function is 2x + 4 - ( 1 / x-1). The correct option is A.
<h3>What is an expression?</h3>
The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.
Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.
Given that the functions are f(x) = x + 2 and h(x) = 1 / x-1. The value of the function 2f(x) – h(x) will be calculated as,
E = 2f(x) – h(x)
E = 2( x + 2 ) - ( 1 / x-1)
E = 2x + 4 - (1/x-1)
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You're correct, the answer is C.
Given any function of the form
, then the derivative of y with respect to x (
) is written as:
In which
is any constant, this is called the power rule for differentiation.
For this example we have
, first lets get rid of the quotient and write the expression in the form
:
Now we can directly apply the rule stated at the beginning (in which
):
Note that whenever we differentiate a function, we simply "ignore" the constants (we take them out of the derivative).
From the question, we know that we will be looking at <3, <4, and angles TKL and TLK. That being said, since <3 is congruent to <4, that means that angles TKL and TLK, which are each supplementary to either angle 3 or 4, are congruent because, since angles 3 and 4 are congruent, they are congruent because the supplements of congruent angles are congruent.
