Answer:
8.06
Step-by-step explanation:
a^2 + b^2 = c^2
4^2 + 7^2 = c^2
16 + 49 = c^2
65= c^2
Find the square root of 65
8.06
<u>Answer:</u>
The Ranking Percentile is (B) 97.5%
<u>Explanation
:</u>
To find the percentile rank we need to find the z- score. After finding the z-score match this value with the corresponding value in z-score table.
Formula to find the z-score
Z-score=
Substituting the values in the above equation, we find
Z-score= 
=2
So, the Z-score is +2
Now, the corresponding value of Z-score 2 in the table is 0.9772
or the percentile score is 97.72 ~ 97.5
.
D) these two figures are similar they don't look similar at first because the X'Z'Y' is more upwards. But they are congruent meaning they are similar or exactly the same almost. This basically tells me that I need to use translation.
E) I can use reflection to get XYZ into X'Y'Z' by reflecting it across the x-axis. I could also use translation and move it up 6 and then move it to the right.
C) The last one I could use is rotation and move it around around 45* or something close to the the other one.
Answer:
P(cell has at least one of the positive nickel-charged options) = 0.83.
P(a cell is not composed of a positive nickel charge greater than +3) = 0.85.
Step-by-step explanation:
It is given that the Nickel Charge Proportions found in the battery are:
0 ==> 0.17
.
+2 ==> 0.35
.
+3 ==> 0.33
.
+4 ==> 0.15.
The numbers associated to the charge are actually the probabilities of the charges because nickel is an element that has multiple oxidation states that is usually found in the above mentioned states.
a) P(cell has at least one of the positive nickel-charged options) = P(a cell has +2 nickel-charged options) + P(a cell has +3 nickel-charged options) + P(a cell has +4 nickel-charged options) = 0.35 + 0.33 + 0.15 = 0.83.
Or:
P(a cell has at least one of the positive nickel-charged options) = 1 - P(a cell has 0 nickel-charged options) = 1 - 0.17 = 0.83.
b) P(a cell is not composed of a positive nickel charge greater than +3) = 1 - P(a cell is composed of a positive nickel charge greater than +3)
= 1 - P(a cell has +4 nickel-charged options) '.' because +4 is only positive nickel charge greater than +3
= 1 - 0.15
= 0.85
To summarize:
P(cell has at least one of the positive nickel-charged options) = 0.83!!!
P(a cell is not composed of a positive nickel charge greater than +3) = 0.85!!!
Additive Identity Property is the answer.
