Answer:
Step-by-step explanation:
We know that for two similar matrices 
and 
exists an invertible matrix 
for which
![[tex]B = P^{-1} AP](https://tex.z-dn.net/?f=%5Btex%5DB%20%3D%20P%5E%7B-1%7D%20AP)
[/tex]
∴ 
Also 
and 
∴
so, 
The "relative frequency" is
(number of times a blue marble came out)
divided by
(total number of trials before everybody got bored and quit) .
-- The relative frequency of blue was (20/60) = (33 and 1/3) % .
(Even though 38.5% of the marbles in the jar are blue,
they didn't get picked that often.)
-- The relative frequency of green was (18/60) = 30 % .
(Even though only 26.9% of the marbles in the jar are green,
they got picked more often than that.)
-- The relative frequency of red was (22/60) = (36 and 2/3) % .
(Even though 42.3% of the marbles in the jar are red,
they didn't get picked that often.)
Change everything into 10ths as follows:
1/10 + 2.5/10 = 3.5/10 of an hour to make one bracelet. Then change to 20ths so the numerator is a whole number.
Divide your time available by the time it takes to make one.
21
4 = 420= 15 bracelets
7 28
20
(as a whole number there was no fraction or remainder to round off)
