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Kobotan [32]
3 years ago
6

I need help with this question! Will mark brainliest :)

Mathematics
2 answers:
nadya68 [22]3 years ago
5 0

Answer:

The answer is the third option, y=3x-2

Explanation:

I'm horrible at explaining, but basically the y-axis is increasing by 3's so it's not negative, and to find the y-axis, we simply put a 0 ontop of the 1 in the x-axis, and across that we get -2 because the y-axis is increasing by 3's.

So sorry for my messy explanation, but I hope it helps :)

Dvinal [7]3 years ago
3 0

Answer:

y=3x-2

Step-by-step explanation:

you find the 3 (the slope) by seeing how much the y value grows

the -2 is the value of the y-intercept (more clear on a graph) but it's when the point is (0,__) so you subtract 3 from 1.

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A genetic experiment involving peas yielded one sample of offspring consisting of 437437 green peas and 129129 yellow peas. Use
navik [9.2K]

Answer:

The null hypothesis: \mathbf{H_o: p=0.27}

The alternative hypothesis: \mathbf{H_1: p \neq 0.27}

Test statistics : z = −2.30

P-value:  = 0.02144

Decision Rule: Since the p-value is lesser than the level of significance; then we reject the null hypothesis.

Conclusion: We accept the alternative hypothesis and  conclude that under the same​ circumstances the proportion of offspring peas will be yellow is not equal to 0.27

Step-by-step explanation:

From the given information:

Let's state the null and the alternative hypothesis;

Since The claim is that 27%  of the offspring peas will be yellow.

The null hypothesis state that the proportion of offspring peas will be yellow is equal to 0.27.

i.e

\mathbf{H_o: p=0.27}

The alternative hypothesis  state that the proportion of offspring peas will be yellow is not equal to 0.27

\mathbf{H_1: p \neq 0.27}

<u>The test statistics:</u>

we are given 437 green peas and 129 yellow apples;

Hence;

\hat p = \dfrac{x}{n}

where ;

\hat p = sample proportion

x = number of success

n = total number of the sample size

\hat p = \dfrac{129}{437+129}

\hat p = \dfrac{129}{566}

\mathbf{\hat p = 0.2279}

Now; the test statistics can be computed as :

z = \dfrac { \hat p -p }{\sqrt {\dfrac{p(1-p)}{n}  } }

z = \dfrac {0.2279 -0.27 }{\sqrt {\dfrac{0.27(1-0.27)}{566}  } }

z = \dfrac {-0.043 }{\sqrt {\dfrac{0.27(0.73)}{566}  } }

z = \dfrac {-0.043 }{\sqrt {\dfrac{0.1971}{566}  } }

z = \dfrac {-0.043 }{\sqrt {3.48233216*10^{-4} } }

z = \dfrac {-0.043 }{0.01866} }

z = −2.30

C. P-value

P-value = P(Z < z)

P-value = P(Z< -2.30)

By using the ​ P-value method and the normal distribution as an approximation to the binomial distribution.

from the table of standard normal distribution

move left until the first column is reached. Note the value as –2.0

move upward until the top row is reached. Note the value as 0.30

find the probability value as 0.010724 by the intersection of the row and column values gives the area to the left of

z = -2.30

P- value = 2P(z ≤ -2.30)

P-value = 2 × 0.01072

P - value = 0.02144

Decision Rule: Since the p-value is lesser than the level of significance; then we reject the null hypothesis.

Conclusion: We accept the alternative hypothesis and  conclude that under the same​ circumstances the proportion of offspring peas will be yellow is not equal to 0.27

8 0
3 years ago
If A ⊂ B, then A ∩ B = ∅. <br> true<br> false
Aloiza [94]

Answer: false

Step-by-step explanation:

4 0
2 years ago
Is the quotient positive or negitive
ArbitrLikvidat [17]
I guess positive bcuz - -=+
6 0
3 years ago
Read 2 more answers
What is the simplified form of the following expression?
USPshnik [31]

Option C:

$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}

Solution:

Given expression is

$\sqrt[3]{\frac{4 x}{5}}

Note: \sqrt[3]{125}=\sqrt[3]{{5^3}}  = 5

To find the correct expression for the above simplified expression.

Option A: \frac{\sqrt[3]{4 x}}{5}

5 can be written as \sqrt[3]{125}.

$\frac{\sqrt[3]{4 x}}{5}=\frac{\sqrt[3]{4 x}}{\sqrt[3]{125} }

       $=\sqrt[3]{\frac{4x}{125} }

It is not the given simplified expression.

Option B: \frac{\sqrt[3]{20 x}}{5}

$\frac{\sqrt[3]{20 x}}{5}=\frac{\sqrt[3]{20 x}}{\sqrt[3]{125} }

         $=\sqrt[3]{\frac{20x}{125} }

Cancel the common factor in both numerator and denominator.

         $=\sqrt[3]{\frac{4x}{25} }

It is not the given simplified expression.

Option C: \frac{\sqrt[3]{100 x}}{5}

$\frac{\sqrt[3]{100 x}}{5}=\frac{\sqrt[3]{100 x}}{\sqrt[3]{125} }

           $=\sqrt[3]{\frac{100x}{125} }

Cancel the common factor in both numerator and denominator.

           $=\sqrt[3]{\frac{4 x}{5}}

It is the given simplified expression.

Option D: \frac{\sqrt[3]{100 x}}{125}

$\frac{\sqrt[3]{100 x}}{125}=\frac{\sqrt[3]{100 x}}{5^3}

It is not the given simplified expression.

Hence Option C is the correct answer.

$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}

3 0
3 years ago
4 x (2 x 7) = (4 x 2) x ___
natka813 [3]

Answer:

x=0

Step-by-step explanation:

8 0
3 years ago
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