First, we simplify 6x+2y=36 into 3x+y=18 by dividing by 2. This means that y=-3x+18.
The sum
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can be written as:
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,
<span>
from the binomial expansion formula: </span>
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.
<span>
Thus, substituting </span>y=-3x+18 and simplifying we have<span>
</span>
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

.
This is a parabola which opens upwards (the coefficient of x^2 is positive), so its minimum is at the vertex. To find x, we apply the formula -b/2a. Substituting b=-108, a=10, we find that x is 108/20=5.4.
At x=5.4, the expression
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, which is equivalent to
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, takes it smallest value.
Substituting, we would find
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=32.4 This is the smallest value of the expression.
For x=5.4, y=-3x+18=-3(5.4)+18=1.8.
Answer: (5.4, 1.8)
Answer: The system of equations are
x + y = 10
3.75x + 2.5y = 35
Step-by-step explanation:
Let x represent the number of cupcakes that Camila bought.
Let y represent the number of brownies that Camila bought.
She bought a total of 10 cupcakes and brownies altogether. This would be expressed as
x + y = 10
Camila and her children went into a bakery and she bought $35 worth of cupcakes and brownies. Each cupcake costs $3.75 and each brownie costs $2.50. This would be expressed as
3.75x + 2.5y = 35
Answer:
x ≥ 6.
Step-by-step explanation:
Given : Kathy swims at least 6 laps every day.
To find: Write an inequality to show how long Kathy swims each day.
Solution : We have given that Kathy swims at least 6 laps every day.
We can see from given statement Kathy can swim 6 laps or greater then 6 laps in a day.
Then we use greater than or equal to sign ( for at least)
Since x ≥ 6.
Therefore, x ≥ 6.
Answer:
2 2/5
Step-by-step explanation:
Given 4/5÷1/3
Multiply 4/5 with the reciprocal of 1/3 as shown;
= 4/5 × 1/(1/3)
= 4/5 × 3/1
= 12/5
= 2 2/5
The quotient is 2 2/5
The trick is to exploit the difference of squares formula,

Set a = √8 and b = √6, so that a + b is the expression in the denominator. Multiply by its conjugate a - b:

Whatever you do to the denominator, you have to do to the numerator too. So

Expand the numerator:






So we have

But √12 = √(3•4) = 2√3, so
