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alina1380 [7]
3 years ago
11

What property is shown below if q=r and r=s, then q=s

Mathematics
2 answers:
Archy [21]3 years ago
5 0
Transitive Property
Since transitive property is a=b, b=c, then a=c. In this problem, since q is related to r while r is related to s. Then q has to be related to a as well.
TEA [102]3 years ago
4 0

Answer:

Transitivity

Step-by-step explanation:

if q=r and r=s, then q=s

It is by the property of TRANSITIVITY.

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Rewrite the expression with rational exponents as a radical expression.
nexus9112 [7]

Answer:

If the expression is 4x^\frac{3}{7}, then the answer is the first option.

If the expression is (4x)^\frac{3}{7}, then the answer is the third option.

Step-by-step explanation:

Remember that when you have a radical expression in the form \sqrt[n]{x}, you can rewrite as:

=x^\frac{1}{n}

Then:

- If the expression is 4x^\frac{3}{7}, then you can rewrite it in the following radical form:

=4\sqrt[7]{x^3} (This form matches with the first option.)

- If the expression is (4x)^\frac{3}{7}, then you can rewrite it in the following radical form:

=\sqrt[7]{(4x)^3} (This form matches with the third option).

7 0
3 years ago
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A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 340 babies were​ born, a
Bas_tet [7]

Answer:

The 99% confidence interval estimate of the percentage of girls born is (0.8, 0.9).

b)Yes, the proportion of girls is significantly different from 0.5.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

In the study 340 babies were​ born, and 289 of them were girls. This means that n = 340, \pi = \frac{289}{340} = 0.85

Use the sample data to construct a 99​% confidence interval estimate of the percentage of girls born.

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{340}} = 0.85 - 2.575\sqrt{\frac{0.85*0.15}{400}} = 0.80

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{340}} = 0.85 + 2.575\sqrt{\frac{0.85*0.15}{400}} = 0.90

The 99% confidence interval estimate of the percentage of girls born is (0.8, 0.9).

Does the method appear to be ​effective?

b)Yes, the proportion of girls is significantly different from 0.5.

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3 years ago
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Answer:

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Step-by-step explanation:

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