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vodomira [7]
3 years ago
12

During lunch on Friday, 45 students in the 7th

Mathematics
2 answers:
goldenfox [79]3 years ago
8 0
If 25% is 45 students, then 100% is 180 students. There are 180 students in the entire 7th grade class.
marin [14]3 years ago
4 0

Answer:

135

Step-by-step explanation:

You might be interested in
The population of a species of rabbit triples every year. This
jok3333 [9.3K]

Answer:

"4" represents that there are 4 rabbit in the beginning.

Step-by-step explanation:

Given that the population of a species of rabbit triples every year. This

can be modeled by function f\left(x\right)=4\left(3\right)^x and f(5) = 972.

Now we need to find about what does the 4 represent in the given function.

We know that exponential function is given by f\left(x\right)=a\left(b\right)^x. Where "a" represents the initial amount.

we have a=4 in given function f\left(x\right)=4\left(3\right)^x.

So that means "4" represents that there are 4 rabbit in the beginning.

3 0
3 years ago
Determine the equation, in vertex form, of a parabola that has been:
Dennis_Churaev [7]

Answer:

a)\ y=-(x-5)^2;\\b)\ y=4x^2-5;\\c)\ (y-2)^2=4*(x+3).

Good luck!

4 0
2 years ago
Solve the system <br> 2x+2y+z=-2 <br> -x-2y+2z=-5<br> 2x+4y+z=0
drek231 [11]

The values of (x,y,z) are (3,-1,-2) , if the given are equations 2x+2y+z=- 2,-x-2y+2z=-5 and 2x+4y+z=0.

Step-by-step explanation:

The given is,

                          2x+2y+z=- 2.......................................(1)

                         -x-2y+2z=-5......................................(2)

                            2x+4y+z=0.........................................(3)

Step:1

           Equation (2) is multiplied by -1            ( Eqn(2) × -1 )

                                         x+2y-2z=5.............................(4)

          Subtract the equation (1) and (4)

                                        2x+2y+z=- 2

                                         x+2y-2z=5

                 ( - )

           (2x-x)+(2y-2y)+(z+2z)=(-2-5)

                                                  x+3z=-7......................(5)

Step:2

          Equation (2) is multiplied by -2                 ( Eqn(2) × -2)

                                        2x+4y-4z=10........................(6)

         Subtract equation (6) and (3),                  

                                        2x+4y-4z=10

                                         2x+4y+z=0

                   ( - )

       (2x-2x)+(4y-4y)+(-4z-z)= (10-0)

                                                     -5z=10

                                                         z = - \frac{10}{5}

                                                         z = -2

         From the equation (5),

                                                  x+3z=-7  

                                          x+(3)(-2)=-7

                                                           x = -7+6

                                                            x = -1

         From equation (1),

                                            2x+2y+z=- 2

          Substitute x and z values,

                               (2)(-1)+2y+(-2)=-2

                                                     2y - 4=2

                                                           2y=4-2

                                                           2y=2

                                                            y=\frac{2}{2}

                                                             y = 1

Step:3

                Check for solution,

                                  -x-2y+2z=-5

                Substitute x,y and z values,

               -(-1)-(2)(1)+(2)(-2)=-5

                                         1-2-4=-5

                                                    -5 = -5

Result:

              The values of (x,y,z) are (3,-1,-2) , if the given are equations 2x+2y+z=- 2,-x-2y+2z=-5 and 2x+4y+z=0.

8 0
4 years ago
Can someone please help me
Irina18 [472]

Answer:

-11, -5, -23, 7

Step-by-step explanation:

plug in the h value into equation

-2(2)-7

-11

-2(-1)-7

-5

-2(8)-7

-23

-2(-7)-7

7

5 0
3 years ago
What is the product?<br><br> 4 cubed times 4 Superscript negative 3<br> 0<br> 1<br> 4<br> 6
Julli [10]

Answer:

4³ × 4 ^-3

Use the rules of indices

You will get

4^3-3

= 4^0

= 1

Hope this helps

4 0
3 years ago
Read 2 more answers
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