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vodomira [7]
3 years ago
12

During lunch on Friday, 45 students in the 7th

Mathematics
2 answers:
goldenfox [79]3 years ago
8 0
If 25% is 45 students, then 100% is 180 students. There are 180 students in the entire 7th grade class.
marin [14]3 years ago
4 0

Answer:

135

Step-by-step explanation:

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It takes 15 minutes to fill a 375 gallon tank with oil how many gallons are pumped into the tank in 1 minute
Nikitich [7]

Answer:

25

Step-by-step explanation:

It takes 15 minutes to fill a 375 gallon tank with oil how many gallons are pumped into the tank in 1 minute

375÷15=25

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4 years ago
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Select all sets in which the number
strojnjashka [21]

Answer:

A

E

Step-by-step explanation:

a rational number can be expressed as fraction. well, that is what the number 8/9 is.

so, A is a correct option.

as such it is automatically also a member of the real numbers (which is a superset of rational numbers). so, E is a correct option.

all other options are wrong.

8/9 is not a natural number (1, 2, 3, 4, ...).

it is not a whole number (0, 1, 2, 3, 4, ...).

it is not an integer (... , -2, -1, 0, 1, 2, 3, ...).

and as it is a rational number, it is automatically not an irrational number.

7 0
3 years ago
please help. No links or fake answers. If your going to answer, may you please do one screenshot at the least. Thank you for you
Lady bird [3.3K]

Answer:

29

Step-by-step explanation:

7 0
3 years ago
Will give brainliest!
miv72 [106K]

Answer:

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6 0
3 years ago
Expand (2x+2)^6<br> How would you find the answer using the binomial theorem?
Yanka [14]

Answer:

Step-by-step explanation:

\displaystyle\\\sum\limits _{k=0}^n\frac{n!}{k!*(n-k)!}a^{n-k}b^k .\\\\k=0\\\frac{n!}{0!*(n-0)!}a^{n-0}b^0=C_n^0a^n*1=C_n^0a^n.\\\\ k=1\\\frac{n!}{1!*(n-1)!} a^{n-1}b^1=C_n^1a^{n-1}b^1.\\\\k=2\\\frac{n!}{2!*(n-2)!} a^{n-2}b^2=C_n^2a^{n-2}b^2.\\\\k=n\\\frac{n!}{n!*(n-n)!} a^{n-n}b^n=C_n^na^0b^n=C_n^nb^n.\\\\C_n^0a^n+C_n^1a^{n-1}b^1+C_n^2a^{n-2}b^2+...+C_n^nb^n=(a+b)^n.

\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\

(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+  \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.

8 0
2 years ago
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