Question

Rewrite as a product of two factors: 3 + 18d + 21y​

Answer 1

Answer:

$\huge { \red{\boxed{ \boxed{ \tt \: 3(1 + 6d + 7y)}}}}$

Step-by-step explanation:

to understand this

you need to know about:

• factoring

let's solve:

in the following expression

everytime 3 is common

(3×1)+(3×6d)+(3×7d)

therefore if you take 3 from every expression we get

• 3(1+6d+7y)

which is a product of two factors

Answer 2

Answer:

the Expression is :

(3) × (1 + 6d + 7y)

Step-by-step explanation:

here's the solution : -

=》

$3 + 18d + 21y$

=》

$(3 \times 1 )+ (3 \times 6d) + (3 \times 7y)$

now, since 3 is common in all terms let's take it out.

=》

$3 \times (1 + 6d + 7y)$

=》so, ,we got the above expression as product of 3 and ( 1 + 6d + 7y ) as factors.