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Radda [10]
3 years ago
9

Last weekend, Mia ran 5% of a mile and Terrel ran 5/15 of a mile. Who ran a

Mathematics
1 answer:
Tcecarenko [31]3 years ago
4 0

Answer:

Terrel ran a larger portion of mile

Step-by-step explanation:

5% of a mile is approximately

0.05 miles

5/15 of a mile is approximately

0.33 miles

so Mia ran 0.05 miles, Terrel ran 0.33 miles

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Adolescences is the answer
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In △BCD, H is the centroid. If HF=6 find BF.
astra-53 [7]

Answer:

18

Step-by-step explanation:

The centroid of a triangle is located ⅓ of the distance from each side to the opposite vertex

So HF=⅓BF

So BF=3xHF=3x6=18

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3 years ago
How to simplify a square root
LenaWriter [7]

Answer:

Step-by-step explanation:

A square root can't be simplified any further if there are no 2 identical factors remaining and every term under the radical symbol is a prime number

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3 years ago
Find the range median first and third interquartile range for each data set
liraira [26]

Answer:

Range = 1.8

Median = 6.3

First Quartile = 6.3

Thrid Quartile = 6.8

Interquartile Range =  0.5

Step-by-step explanation:

First we need to arrange the data set from lowest to highest.

4.9, 5.8, 6.1, 6.2, 6.3, 6.3, 6.4, 6.6, 6.7, 6.7

To find the range of the data set, we simply take the highest value and subtract it to the lowest value.

Range = 6.7 - 4.9

Range = 1.8

To find the Median we need to get the middle number of the range. In this case there are two numbers in the middle of the set.

So we get both of them and get their average.

Median = 6.3 + 6.3 /2

Median = 6.3

To get the first quartile, we simply get the median of the lower of the data set.

4.9, 5.8, 6.1, 6.2, 6.3

The median of the first quartile is 6.1.

To get the third quartile, we get the median of the upper half of the data set.

6.3, 6.4, 6.6, 6.7, 6.7

The median of the third quartile is 6.6

To get the interquartile range, we need to subtract the median of the third quartile to the median of the first quartile.

Interquartile Range = 6.6 - 6.1

Interquartile Range = 0.5

Answer:

Range = 32

Median = 17.5

First Quartile = 15

Thrid Quartile = 19

Interquartile Range =  4

Step-by-step explanation:

First we need to arrange the data set from lowest to highest.

4, 9, 15, 16, 17, 18, 18, 19, 19, 36

To find the range of the data set, we simply take the highest value and subtract it to the lowest value.

Range = 36 - 4

Range = 32

To find the Median we need to get the middle number of the range. In this case there are two numbers in the middle of the set.

So we get both of them and get their average.

Median = 17 + 18 /2

Median = 17.5

To get the first quartile, we simply get the median of the lower of the data set.

4, 9, 15, 16, 17,

The median of the first quartile is 15.

To get the third quartile, we get the median of the upper half of the data set.

18, 18, 19, 19, 36

The median of the third quartile is 19.

To get the interquartile range, we need to subtract the median of the third quartile to the median of the first quartile.

Interquartile Range = 19 - 15

Interquartile Range = 4

6 0
3 years ago
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Please identify the common angles and sides or if there are non. Explain all work please!
stepladder [879]

Answers:

Common angles: ΔBGC and ΔGDC

Common sides: ΔGE and ΔAG

A common angle is a triangle that exists in two or both of the triangles.

Here, the common angles should be ΔBGC and ΔGDC.

These two angles are triangles, and they consist in both triangles.

A common side is when two angles have one vertex in the same area.

Here, we see that the common sides are ΔGE, because they intersect.

Another common side we see here is ΔAG, because they also intersect.

Hope this answer helps you!

3 0
3 years ago
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