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Gekata [30.6K]
3 years ago
6

PLEASE HELP IS IT YVES?

Mathematics
2 answers:
Alex17521 [72]3 years ago
6 0

The answer is the one about Mia because if you go to the left it says 35 and if you go down it says 7

artcher [175]3 years ago
4 0
The answer is B. Carlos worked two hours and earned $20
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200 AND 50

Step-by-step explanation:

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Lilly was working on a report on Italian and Spanish scientists. She decided to find a 96 percent confidence interval for the di
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The answer is "Option A and Option B".

Step-by-step explanation:

In question 1:

In all cases, the entire population is measured so that the actual medium discrepancy could be measured as well as an interval of trust cannot be used.

This issue would be that she calculated the ages with all representatives of both classes, such that she measured a whole population. It's not necessary.

In question 2:

When the p-value is 0.042. At 90% trust and 92% trust level 11 (p-value below 0.10 and 0.08) are not included. however the biggest confidence level of 92%. Consequently, the largest trust level where the 11 is Not included in the trust interval is 92% trust.

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3 years ago
Binomial Probability
ASHA 777 [7]

Answer:

4.39% theoretical probability of this happening

Step-by-step explanation:

For each coin, there are only two possible outcomes. Either it lands on heads, or it lands on tails. The probability of a coin landing on heads is independent of other coins. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Theoretically, a fair coin

Equally as likely to land on heads or tails, so p = \frac{1}{2} = 0.5

10 coins:

This means that n = 10

What is the theoretical probability of this happening?

This is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{10,2}.(0.5)^{2}.(0.5)^{8} = 0.0439

4.39% theoretical probability of this happening

6 0
4 years ago
Martine wants to have $50,000 in 10 years for college. What single deposit would he need to make now into an account that pays 4
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$ 21,500.00 dollars total
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3 years ago
A bag contains five white balls and five black balls. Your goal is to draw two black balls.
umka21 [38]

Answer:

a.) the probability that both the ball drawn are black  = \frac{10}{45} = \frac{2}{9}

b.) Sum of all the probabilities = \frac{\frac{2}{9} }{1 - \frac{2}{9} }  = \frac{\frac{2}{9} }{\frac{8}{9} }  = \frac{2}{8} =\frac{1}{4} = 0.25

Step-by-step explanation:

a) two balls are drawn at random .

   total number of balls   =  10

 number of black balls    =  5

  number of white balls    = 5.

   the number of ways two balls can be drawn = \binom{10}{2}  = \frac{10!}{2! 8!}  = \frac{10\times9}{2}  = 45

  the number of ways two black balls can be drawn = \binom{5}{2}  = \frac{5!}{2! 3!}  = \frac{5\times4}{2}  = 10

   the probability that both the ball drawn are black  = \frac{10}{45} = \frac{2}{9}

b) probability that First draw of two black balls = \frac{2}{9}

  probability that first draw is of two white balls is and second draw is of

  two black balls  = \frac{2}{9} \times\frac{2}{9}

  Probability that first two draws are of white balls and the third draw is of

  two black balls = \frac{2}{9} \times\frac{2}{9} \times\frac{2}{9}

  This is a geometric sequence and the final probability will be the sum of    

  all such probabilities, where we can take the the sequence to be an infinite series and the first term is \frac{2}{9} and the common ratio is \frac{2}{9}  which is less than 1.

  Sum of all the probabilities = \frac{\frac{2}{9} }{1 - \frac{2}{9} }  = \frac{\frac{2}{9} }{\frac{8}{9} }  = \frac{2}{8} =\frac{1}{4} = 0.25

3 0
4 years ago
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