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ddd [48]
3 years ago
8

I NEDD HELPP PLESASEEEEEEEEEEEEEEEEEEEEEEEEEEE

Mathematics
1 answer:
miv72 [106K]3 years ago
8 0

Answer:

Alright what do you need help with

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Convert 714.81 mm to meters. (please show the steps to how you did the problem.)
zaharov [31]

Answer:

0.7148 meter

Step-by-step explanation:

you have to divied 714.81 by 1000 to get 0.7148 meter

5 0
3 years ago
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Given the linear equation 2x + y = 6, perform the necessary operations to put the equation into the proper general form. Explain
likoan [24]

Step-by-step explanation:

The general equation is y = mx + c...

The given equation is 2x + y = 6

Firstly, move everything on the left except the y to the right.i.e.

y = 6 - 2x

Secondly, rearrange the values on the right to look just like the general equation.

y = -2x + 6

The equation is now in proper general form because it matches the format laid down.

3 0
3 years ago
Please help! <br> Simplify. Your answer should contain only positive exponents.
maxonik [38]

Answer:

\frac{1}{4k^3}

Step-by-step explanation:

It's already in a form that only ha positive exponents.  Just to state it though you could rewrite it as k*(4k^{4})^{-1} or k*4^{-1}*k^{-4}  The question asks for positive exponents though so yu don't need to do that.

You also need to know \frac{x^a}{x^b}=x^{a-b} so in this case \frac{k}{k^4}=\frac{k^1}{k^4} =k^{1-4}=k^{-3}=\frac{1}{k^3}

so \frac{k}{4k^4}=\frac{1}{4}*\frac{k}{k^4}=\frac{1}{4}*\frac{1}{k^3}=\frac{1}{4k^3}

3 0
3 years ago
Square root 1.96? is rational irrational
Kruka [31]

Answer:

Rational

Step-by-step explanation:

An irrational number is a number with forever continuing decimals. Plug it into the calc and you can see if there is a long decimal line that ends. You should get 1.4 in the calc, and since it does end, it is a rational number.

4 0
3 years ago
Oliver shot 8 free throws at practice, making 6 free throws and missing 2 free throws. If Oliver equally likely to make a free t
ryzh [129]

Answer:

"Round" (and any subsequent words) was ignored because we limit queries to 32 words.

Hope it can help you.....

7 0
3 years ago
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