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ella [17]
3 years ago
8

What basic trigonometric identity would you use to verify that (sin2x + cos2x)/cosx=secx

Mathematics
2 answers:
Oksana_A [137]3 years ago
7 0

Answer:

Step-by-step explanation:

sin(2x) = 2 sin(x) cos(x) cos(2x) = cos2(x) – sin2(x) = 1 – 2 sin2(x) = 2 cos2(x) – 1. Now I am not sure if this is right but I remember another similar formula. Here is the correct formula cot x = cos x / sin x

2 ) ( sin² x + cos² x ) / cos x = sec x

1/cos x = sec x

sec x = sec x

cos² x + sin² x = 1

Papessa [141]3 years ago
3 0

Step-by-step explanation:

\frac{ \ {sin}^{2} x +  { \cos}^{2} x}{cos \: x}   = sec \: x \\  \\ LHS  \\ = \frac{ \ {sin}^{2} x +  { \cos}^{2} x}{cos \: x}    \\  \\  =  \frac{ 1}{cos \: x} \:( \because \:    \ {sin}^{2} x +  { \cos}^{2} x = 1) \\  \\  = sec \: x \\  = RHS \\

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