Tolerance = 1% = 0.01 on a shaft of 15 in
Tolerance in inches = 15 x 0.01 =0.15 in
Since it' s a tolerance the acceptable error is either +0.15in or -0.15 in
Answer:
Step-by-step explanation:
1)4.5m+4.7=20m+47
4.5m-20m=47-4.7
-15.5m=42.2
m=-2.72
2)14+21w=7(2+3w)
41+21w=14+21w
21w-21w=14-41
3)49r+35=7(7r+35)
49r+35=49r+245
49r-49r=245-35
4)9(8h-3)=72h-27
72h-27=72h-27
72h-72h=-27+27
5)5.2+5.3t=10+15t
5.3t-15t=10-5.2
-9.7t=4.8
t=4.8/-9.7
t=0.49
6)6f+3.111=18f-33
6f-18f=-33-3.111
-12f=-36.111
f=-36.111/-12
f=3.01
For this case we have that according to the order of algebraic operations PEMDAS, the multiplications have priority over the addition and subtraction, then, we have the following expression:

Thus, the value of the expression is 1000.
Answer:

For this case we have to define root properties:
![\sqrt [n] {a ^ n} = a ^ {\frac {n} {n}} = a](https://tex.z-dn.net/?f=%5Csqrt%20%5Bn%5D%20%7Ba%20%5E%20n%7D%20%3D%20a%20%5E%20%7B%5Cfrac%20%7Bn%7D%20%7Bn%7D%7D%20%3D%20a)
In addition, we know that:

On the other hand:

Thus, we can rewrite the given expression as:

ANswer:
Option B
Answer:
The mean is 11.5 minutes and the standard deviation is of 6.64 minutes
Step-by-step explanation:
An uniform probability is a case of probability in which each outcome is equally as likely.
For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.
The mean is:

The standard deviation is:

Arrival time of 9:18 am and a late arrival time of 9:41 am.
9:41 is 23 minutes from 9:18. So the time is uniformily distributed between 0 and 23 minutes, so a = 0, b = 23.
Mean:

Standard deviation:

The mean is 11.5 minutes and the standard deviation is of 6.64 minutes