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Soloha48 [4]
3 years ago
14

If PQ and RS intersect to form four right angles which statement is true

Mathematics
2 answers:
Rus_ich [418]3 years ago
7 0
Given that PQ and RS intersect to form four right angles, then they form an angle of 90 degrees, this implies that:
if the meet at point O, 
then;
∠POR=∠POS=∠QOS=∠ROQ=90°
Therefore the correct statement is:
PQ is perpendicular to RS
that is to mean:
PQ⊥RS
The answer is C.
Aliun [14]3 years ago
3 0

Answer:

Given: PQ and RS intersect to form four right angles.

Option C is correct.i.e., PQ ⊥ RS

Because Perpendicular means a line intersecting another at right angles and making 4 right angles between them. Here, also PQ intersect with RS at right angles and makes 4 right angle

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3 years ago
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sertanlavr [38]

Answer:

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Elza [17]
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6 0
4 years ago
Helpp!!!<br>(1-sin2A)(1+cot2A)=cot2A​
lord [1]

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1 - sin(2<em>A</em>) - cos(2<em>A</em>) = 0

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Multiply both sides by 1/√2, which we want to do because cos(<em>π</em>/4) = sin(<em>π</em>/4) = 1/√2. This gives

cos(<em>π</em>/4) sin(2<em>A</em>) + sin(<em>π</em>/4) cos(2<em>A</em>) = 1/√2

Then condense the left side as

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(where <em>n</em> is any integer)

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4 0
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