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3 years ago

Simplify the following expression

Mathematics

1 answer:

Fantom [35]3 years ago

8 0

Answer:

Step-by-step explanation:

i am sure 10000% and plz if it is correct can u give me beainlst

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Find a linear approximation of the function f(x)=\sqrt[3]{1+x} at a=0, and use it to approximate the numbers \sqrt[3]{.96} and \

34kurt

$f(x)=\sqrt[3]{1+x}=(1+x)^{1/3}\implies f'(x)=\dfrac1{3(1+x)^{2/3}}$

The linear approximation to $f(x)$ around $x=a$ is then

$L(x)=f(a)+f'(a)(x-a)\approx f(x)$

So the approximation centered at $a=0$ will be

$L(x)=f(0)+f'(0)x=(1+0)^{1/3}+\dfrac x{3(1+0)^{2/3}}$
$L(x)=1+\dfrac x3$

which means we have

$\sqrt[3]{0.96}\approx L(0.96)=1+\dfrac{0.96}3=1.32$

$\sqrt[3]{1.02}\approx L(1.02)=1+\dfrac{1.02}3=1.34$

Compare to the actual values of

$\sqrt[3]{0.96}\approx0.9864$

$\sqrt[3]{1.02}\approx1.0066$

4 0

3 years ago

Suppose that you can buy 5 apples for $2. How much would it cost to<br> buy 17 apples?

Doss [256]

69420 apples all together

7 0

3 years ago

Read 2 more answers

Please help me!! I’ll give brainliest if right , it’s easy too but I don’t get it.

Sindrei [870]

Answer:

Step-by-step explanation:

Provef

In the ∆VXW and ∆ZXY given that

WX~= YX, VX~=ZX and the included angleVXW = the included angleZXY (vertically opposite angles are equal to each other)

Therefore

∆VXW ~= ∆ZXY [SAS Theorem]

Proven

7 0

3 years ago

The following describes a sample. The information given includes the five number summary, the sample size, and the largest and s

lys-0071 [83]

Answer:

$L= Q_1 - 1.5*IQR = 210 -1.5*40 =150$

$U= Q_3 + 1.5*IQR = 250 +1.5*40 =310$

And if we analyze the info provided we have 500 values

Tails: 160,165,167,171,175,...,268,269,269,269,270,270

So as we can see on the tails any values is <150 or >310 so then for this case we cannot consider as outliers any of the values on the tails of the distribution.

Step-by-step explanation:

For this case we have the 5 number summary

(160,210,220,250,270)

So then we have:

minimum = 160 , Q1 = 210, Q2= Median=220, Q3 = 250, Max=270

If we find the interquartile range we got:

$IQR = Q_3 -Q_1 = 250-210 =40$

For this case we need to find the lower and upper limit with the following formulas:

$L= Q_1 - 1.5*IQR = 210 -1.5*40 =150$

$U= Q_3 + 1.5*IQR = 250 +1.5*40 =310$

And if we analyze the info provided we have 500 values

Tails: 160,165,167,171,175,...,268,269,269,269,270,270

So as we can see on the tails any values is <150 or >310 so then for this case we cannot consider as outliers any of the values on the tails of the distribution.

4 0

4 years ago

OMG, GUYSS please helppp this is due in like.. 10 mins.. will give brainliest, please also add an explanation... THANKYOU I LOVE

OleMash [197]

Answer:

19,000 pa.

Step-by-step explanation:

I hope this helps

3 0

3 years ago