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There are 50 deer in a particular forest. The population is increasing at a rate of 15% per year. Which exponential growth function represents
the number of deer y in that forest after x months? Round to the nearest thousandth.
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Answer:
The expression that represents the number of deer in the forest is
y(x) = 50*(1.013)^x
Step-by-step explanation:
Assuming that the number of deer is "y" and the number of months is "x", then after the first month the number of deer is:
y(1) = 50*(1+ 0.15/12) = 50*(1.0125) = 50.625
y(2) = y(1)*(1.0125) = y(0)*(1.0125)² =51.258
y(3) = y(2)*(1.0125) = y(0)*(1.0125)³ = 51.898
This keeps going as the time goes on, so we can model this growth with the equation:
y(x) = 50*(1 - 0.15/12)^(x)
y(x) = 50*(1.013)^x
Y-intercept: 2 because in the formulation y=Mx+b b=the y intercept and in this equation 2 is b
Answer:
Step-by-step explanation:
16/3 / 20/9 = 16/3 x 9/20= 12/5 which is 2 2/5e
Answer:
y = 2.5(x + 2)^2 - 3
The answer is A
Step-by-step explanation:
The general equation for the vertex is
y = a (x + b)^2 + c
a we are not certain about
b = 2
c = - 3
y = a(x + 2)^2 - 3 Now we have to solve for a.
a is found by using the one point we know (0,7) It means when x = 0 y = 7 so just put those two numbers in.
7 = a(0 - 2)^2 - 3
7 = a (- 2)^2 - 3 Add 3 to both sides.
7 + 3 = a(4) Combine 7 and 3
10 = 4a Divide by 4
10/4 = a Do the actual division
2.5 = a
Answer: See above
Answer:
i think that it would be the second one