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3 years ago

Plzz how do i find the area w just the base

Mathematics

2 answers:

Roman55 [17]3 years ago

7 0

Answer:

8x8= 64 divided by 2 = 37

Step-by-step explanation:

Art [367]3 years ago

5 0

The area of a rectangle is equal to its length, l, multiplied by its width, w: A = l x w. Given a pyramid whose base is 10 inches long and 15 inches wide, find area as follows: A = 10 inches x 15 inches = 150 square inches.

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Solve the equation: -2/5 n = -30<br> A. n=-75<br> B. n=-12<br> C. n=12<br> D. n=75

OLEGan [10]

Assuming your equation is: -2/5n = -30

-2/5n = -30 <- We get rid of the "/5n" by multiplying each side by 5n
-2 = -30 * 5n
-2 = -150n
-1 = -75n
75n = 1

But this doesn't match up with any of your answers, so if you wouldn't mind giving me the equation again, i'll work it out

6 0

3 years ago

Read 2 more answers

I need help PLEASE help mee

EastWind [94]

Answer:

Step-by-step explanation:

In order to convert 0.0004578, which is in decimal, to scientific notation, all we need to do in this case is to move our decimal point to the right till we arrive at the first number that is not a zero, and then eliminate all the zero.

In this case, we will have to move the decimal point 4 spaces to our right, which would mean our exponent would be negative. The number of decimal spaces we moved to our right would be the value of our exponent, which is -4 in this case.

Thus, we have:

$4.578 * 10^{-4}$

6 0

4 years ago

PLEASE HELP!

fenix001 [56]

Answer:

Step-by-step explanation:

No because (1,2) falls on the line, and the line is a dotted line, which means that any point on the line is not a solution to the inequality.

5 0

3 years ago

First question, thanks. I believe there should be 3 answers

zysi [14]

Given: The following functions

$A)cos^2\theta=sin^2\theta-1$ $B)sin\theta=\frac{1}{csc\theta}$ $\begin{gathered} C)sec\theta=\frac{1}{cot\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

To Determine: The trigonometry identities given in the functions

Solution

Verify each of the given function

$\begin{gathered} cos^2\theta=sin^2\theta-1 \\ Note\text{ that} \\ sin^2\theta+cos^2\theta=1 \\ cos^2\theta=1-sin^2\theta \\ Therefore \\ cos^2\theta sin^2\theta-1,NOT\text{ }IDENTITIES \end{gathered}$

$\begin{gathered} sin\theta=\frac{1}{csc\theta} \\ Note\text{ that} \\ csc\theta=\frac{1}{sin\theta} \\ sin\theta\times csc\theta=1 \\ sin\theta=\frac{1}{csc\theta} \\ Therefore \\ sin\theta=\frac{1}{csc\theta},is\text{ an identities} \end{gathered}$

$\begin{gathered} sec\theta=\frac{1}{cot\theta} \\ note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ tan\theta cot\theta=1 \\ tan\theta=\frac{1}{cot\theta} \\ Therefore, \\ sec\theta\ne\frac{1}{cot\theta},NOT\text{ IDENTITY} \end{gathered}$

$\begin{gathered} cot\theta=\frac{cos\theta}{sin\theta} \\ Note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ cot\theta=1\div tan\theta \\ tan\theta=\frac{sin\theta}{cos\theta} \\ So, \\ cot\theta=1\div\frac{sin\theta}{cos\theta} \\ cot\theta=1\times\frac{cos\theta}{sin\theta} \\ cot\theta=\frac{cos\theta}{sin\theta} \\ Therefore \\ cot\theta=\frac{cos\theta}{sin\theta},is\text{ an Identity} \end{gathered}$

$\begin{gathered} 1+cot^2\theta=csc^2\theta \\ csc^2\theta-cot^2\theta=1 \\ csc^2\theta=\frac{1}{sin^2\theta} \\ cot^2\theta=\frac{cos^2\theta}{sin^2\theta} \\ So, \\ \frac{1}{sin^2\theta}-\frac{cos^2\theta}{sin^2\theta} \\ \frac{1-cos^2\theta}{sin^2\theta} \\ Note, \\ cos^2\theta+sin^2\theta=1 \\ sin^2\theta=1-cos^2\theta \\ So, \\ \frac{1-cos^2\theta}{sin^2\theta}=\frac{sin^2\theta}{sin^2\theta}=1 \\ Therefore \\ 1+cot^2\theta=csc^2\theta,\text{ is an Identity} \end{gathered}$

Hence, the following are identities

$\begin{gathered} B)sin\theta=\frac{1}{csc\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

The marked are the trigonometric identities

3 0

1 year ago

Find the quotient and remainder of 52 divided by 8

jarptica [38.1K]

Well 52 divided by 8 is 6.2 so..

8 0

3 years ago