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vredina [299]
3 years ago
12

Draw a line representing the "rise" and a line representing the "run" of the line. State the slope of the line in simplest form.

Mathematics
1 answer:
Contact [7]3 years ago
5 0
I think the slope is -4/3 because the line goes up 8 times and go left 6 times before going to the next point which is -8/6 and -8/6 simplified is -4/3.
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15. In the drawing, find the perimeter of triangle BIS.<br>​
Nesterboy [21]

Answer:

29.86 units

Step-by-step explanation:

In the triangle BIS, IT is the bisector of angle BIS,

BI \cong ST.... (given) \\

Let BI = ST = x... (1)

By angle bisector property of a triangle, we have:

\frac{BI}{IS} = \frac{BT}{ST}.... (2)\\\\\frac{x}{12} = \frac{4}{x}\\\\x\times x = 12\times 4\\\\x^2 = 48\\\\x=\sqrt{48}\\\\x = 6.92820323\\\\x = 6.93\\

Therefore,

BI = ST =6.93

Perimeter of triangle BIS

= BI + IS + ST + BT

= 6.93 + 12 + 6.93 + 4

= 29.86 units

3 0
3 years ago
!!20 POINTS!!
Sergeeva-Olga [200]

Answer:

60

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
****WILL GIVE BRAINLIEST TO THE FIRST CORRECT ANSWER****
monitta

All sides are the same, hence, all three angles are the same, and each one of them is 60 degrees. Due to that:

7x + 4 = 60

7x = 56

x = 56/7 = 8

8y + 12 = 60

8y = 48

y = 48/8 = 6

3 0
3 years ago
A trapezoidal prism undergoes a dilation. The surface area of the pre-image is 35 m². The surface area of the image is 315 m². T
Westkost [7]

The original object is called pre-image, and its dilated version is called image. The height of the image for the considered case is 17.4 m

<h3>How does dilation affect length, area, and volume of an object?</h3>

Suppose a figure (pre image) is dilated (dilated image) by scale factor of k.

So, if a side of the figure is of length L units, and that of its similar figure is of M units, then:

<u><em>L = k × M</em></u>

where 'k' will be called as scale factor.

The linear things grow linearly like length, height etc.

The quantities which are squares or multiple of linear things twice grow by square of scale factor. Thus, we need to multiply or divide by <u><em>k²</em></u><em> </em>to get each other corresponding quantity from their similar figures' quantities.

<u><em>So </em></u><u><em>area </em></u><u><em>of </em></u><u><em>first figure </em></u><u><em>= k² × area of second figure</em></u>

Similarly,

<u><em>Volume </em></u><u><em>of first figure = k³ × volume of second figure.</em></u>

It is because we will need to multiply 3 linear quantities to get volume, which results in k getting multiplied 3 times, thus, cubed.

For this case, we're given that;

  • Surface area of pre-image = 35 m²
  • Surface area of dilated image = 315 m²
  • Height of pre-image = 5.8 m
  • Height of dilated image.

Let the scale fator of dilation be k.

Then:

<u><em>So area of pre-image = k² × area of dilated image</em></u>

Thus, we get:

35 = k^2 \times 315\\\\k = \sqrt{\dfrac{35}{315}} = 1/3

(took positive root as scaling is done by non-negative factors as only magnitude matters mostly)

Thus, we get:

Height of pre-image = (1/3) × Height of dilated image (say h)

5.8 = (1/3) \times h\\h = 3 \times 5.8 = 17.4 \rm \: m

Thus, the original object is called pre-image, and its dilated version is called image. The height of the image for the considered case is 17.4 m

Learn more about dilation here:

brainly.com/question/3266920

4 0
2 years ago
Read 2 more answers
Find the area of the triangle whose vertices are (0,4) , (0,0) and (2,0) by plotting them on graph
Luden [163]

Refer to the attached image. Since one vertex is the origin and the other two lay on the coordinate axes, the triangle is a right triangle. This means that, if we consider AB to the be base, AC is his height, and vice versa.

Anyway, it means that the area is given by

A = \cfrac{\overline{AB}\times\overline{AC}}{2}

Since AB is a horizontal segment and AC is a vertical segment, their length is given by the absolute difference of the non-constant coordinate: points A and B share the same x coordinate, so we subtract the y coordinates:

\overline{AB} = |2-0| = |2| = 2

The opposite goes for AC: points A and C share the same y coordinate, so we subtract the x coordinates:

\overline{AC} = |4-0| = |4| = 4

So, the area is

A = \cfrac{2\times 4}{2} = 4

4 0
3 years ago
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