thanks so much for the points
Answer:
The p-value is 0.175
Step-by-step explanation:
We have the null hypothesis 
and the alternative hypothesis 
(two-tailed alternative). Because the sample size is n = 17 and the test statistic is t=-1.421, we know that this last value comes from a t distribution with n-1=17-1=16 degrees of freedom. Therefore, the p-value is given by 2P(T < -1.421) because the p-value is the probability of getting a value as extreme as the observed value and because of the simmetry of the t distribution. Here, T has a t distribution with 16 df and we are using the t distribution because the sample size is small. So, 2P(T < -1.421) = 0.1745
Answer: First equation: 3
Second equation: 6
Step-by-step explanation:
First equation:
The standard equation for a circle is (x-h)^2+(y-k)^2=r^2, where (h,k) is the vertex of the circle and r is the radius
To find the radius, set r^2=9, since 9 is taking the place of r^2.
Square root each side, and only positive values are taken for a radius, so the radius is 3.
Second equation:
Using the same logic, we can find the radius for the second one.
The radius is r^2=36(remember that r^2 is taking place of 36)
Take the square root of both sides(only +), so the radius for the second problem is 6.
>:)
Place the center of the compass at A and extend the compass to point B
<span>draw the circle with center A and radius AB </span>
<span>now move the compass center to point B and draw the circle with center B and radius AB </span>
<span>the two circles will intersect at two points ( you don't really need to draw the entire circles, just enough so that the arcs you draw will intersect in two points) </span>
<span>use a straight edge to connect those two points of intersection, and the line you draw will be the bisector of the given segment AB </span>
<span>( the common radius of the circles you draw doesn't actually have to equal AB, it just has to be greater than one half AB in order for the circles to intersect each other. But the proof that this construction works is a little more elegant if the radii are AB)</span>
