The 2020 ICD-10-CM diagnosis code for cocaine abuse is F14.10
Explanation:
ICD code F01-F99 refers to mental, behavioral, and neuro-developmental disorders.
ICD code F14 stands for cocaine related disorders and F14.1 indicates cocaine abuse.
Cocaine is an addictive illicit drug and abuse effect the body and causes both physical and psychological symptoms.
Short-term signs or effects due to cocaine abuse includes dilated pupils, body temperature, erratic or rapid pulse, high blood pressure and increased heart rate, increased respiratory rate, dilated pupils, lack of appetite and sleep, hyperstimulation with erratic or violent behavior, panic, psychosis etc. Based on the patient’s symptoms and vital signs, the patient’s diagnosis would be cocaine abuse.
Plastids - food and pigment storage
Golgi apparatus - transportation highway of the cell
Ribosomes - protein produces
Mitochondria - powerhouse of the cell
Lysosomes - enzyme producer for digestion
Endoplasmic reticulum - transportation highway of the cell
Answer:
100% of children will have a double heterozygous genotype (EeWw)
Explanation:
A homo-zygous individual is an individual that has two dominant alleles or two recessive alleles for a given gene/<em>locus</em>. A dihybrid cross, also known as Mendelian dihybrid cross, refers to a type of cross in which both parents differ in two observed phenotypic traits which are controlled by two distinct non-linked genes. When both parents are inversely homo-zygous for both genes as in this case (i.e., one parent is homo-zygous dominant for the first gene and homo-zygous recessive for the second gene, while the other parent is homo-zygous recessive for the first gene and homo-zygous dominant for the other), all the F1 will be heterozygous, i.e., all F1 individuals will have the EeWw genotype because each parent can produce only one type of gamete (either Ew or eW). If both genes are subject to complete dominance, then the expected phenotypic ratio of the F2 obtained by crossing double heterozygous individuals will be 9:3:3:1, i.e., 9/16 individuals will have the dominant phenotype for both traits (in this case E_W_ genotype), 3/16 individuals will have the dominant phenotype for the first trait (in this case, dominant earlobe E_ww genotype), 3/16 individuals will have the dominant phenotype for the second trait (in this case, dominant hairline eeW_ genotype), and 1/16 will have the recessive phenotype for both traits (in this case, double recessive eeww genotype).
P goes with true breeding parents. The other two descriptions aren't quite right. F1 refers to the offspring of P. F2 refers to the offspring of F1. The descriptions are already in the correct order.
