X^2+y^2 = 16
can be written as
(x-0)^2+(y-0)^2 = 4^2
We see that the second equation is in the form
(x-h)^2 + (y-k)^2 = r^2
where
(h,k) = (0,0) is the center
r = 4 is the radius
The polar form of the equation is simply r = 4. Why is this? Because the radius is fixed to be 4 no matter what happens with theta. As theta goes from 0 to 360, the points generated all form a circle centered at (0,0) with radius 4.
Answer: r = 4
To solve for 
, we need to isolate it on one side of the equation.
The most important part of this is knowing that whatever we do to one side of the equation, we must also do to the other.
Subtract 32 from both sides of the equation.
Divide both sides of the equation by 
.
Answer: AE=13
Step-by-step explanation: took test
Answer:
(5,-3) in the 4th quadrant
Step-by-step explanation:
