Answer:
The measurement of the angle subtended by an arc with a length of 5/2 pi meters is 149.542°
Step-by-step explanation:
Here, the diameter of the circle = 6 m
Diameter = 2 x RADIUS
So, radius = D / 2 = 6 / 2 = 3 m
Also, the length of the arc = (
) meters
Putting π = 3.14, we get
The length S of the arc =
or, S = 7.85 m
Let us assume the arc subtends angle Ф at the center of the circle.
⇒ S = r Ф
or, Ф = 
⇒Ф = 2.61 radians
Now, 1 Radian = 57.2958 Degrees
⇒ 2. 62 Radian = 2.61 x ( 57.2958 Degrees) = 149.542 °
or, Ф = 149.542°
Hence, the measurement of the angle subtended by an arc with a length of 5/2 pi meters is 149.542°
Try using the equation v= pi(r)^2
Answer:
it's a translation
Step-by-step explanation:
it just moved (3,0). If it were a rotation the y-axis wouldn't be the same. If it were a reflection you would be able to flip the blue triangle onto the red triangle.
Answer:
C 
Step-by-step explanation:
First use the property of logarithms

For the given expression you get
![\log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2+8} }=\log_w(x^2-6)^4-\log_w\sqrt[3]{x^2+8}=\log_w(x^2-6)^4-\log_w(x^2+8)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Clog_w%5Cdfrac%7B%28x%5E2-6%29%5E4%7D%7B%5Csqrt%5B3%5D%7Bx%5E2%2B8%7D%20%7D%3D%5Clog_w%28x%5E2-6%29%5E4-%5Clog_w%5Csqrt%5B3%5D%7Bx%5E2%2B8%7D%3D%5Clog_w%28x%5E2-6%29%5E4-%5Clog_w%28x%5E2%2B8%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
Now use property of logarithms

For your simplified expression, you get
