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3 years ago

HURRY ILL GIVE EXTRA POINTS PLEASE GIVE AND ACTUAL ANSWER PLEASE IM BEGGING Find the value of x.

Mathematics

1 answer:

nadya68 [22]3 years ago

8 0

Answer: its 8

Step-by-step explanation: 5 x is equal too 5 times x and if you do 5 x 8 wich is 40, 40 + 15 =55

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The perimeter of the rectangle is 30 centimeters. What is the length of side c?

Anna35 [415]

P=2a+2c=30

a+c=15

C=15-a

3 0

3 years ago

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The difference of the reciprocal of a number and 7/104 is 3/52 find the number

Yakvenalex [24]

Answer:

Step-by-step explanation:

1/x - 7/104 = 3/52

1/x = 6/104 + 7/104 = 13/104

104/13 = x

7 0

3 years ago

Select the correct expressions. 1 Identify each expression that represents the slope of a tangent to the curve y= * +1 at any po

Olegator [25]

The expressions which represents the slope of a tangent to the curve $y=\frac{1}{x+1}$ at any point (x, y) are:

$f'(x) =limh \rightarrow 0\frac{-h}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{x^2h+2xh+xh^2+h^2 +1}$

<h3>The slope of a tangent to the curve.</h3>

Mathematically, the slope of a tangent line to the curve is given by this equation:

$f'(x) =limh \rightarrow 0\frac{f(x+h)-f(x)}{h}$

Given the function:

$f(x)=y=\frac{1}{x+1}$

When (x + h), we have:

$f(x+h)=y=\frac{1}{x+h+1}$

Next, we would find the derivative of f(x):

$f'(x) =limh \rightarrow 0\frac{\frac{1}{x+h+1} -\frac{1}{x+1}}{h}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -(x+h+1)}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -x-h-1}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{x^2h+2xh+xh^2+h^2 +1}\\\\f'(x) = \frac{-1}{(x+1)(x+1)} \\\\f'(x) = \frac{-1}{(x+1)^2}$

Read more on slope of a tangent here: brainly.com/question/26015157

#SPJ1

5 0

3 years ago

How much is 2+2? I need help<br>I put 4, but is not 4

Ivahew [28]

Sometimes people would say 22. So try 22.

-Dhruva;)

6 0

3 years ago

Factorize completely (2x+2y) (x-y)+(2x-2y)(x+y)

larisa86 [58]

Answer: See below

Explanation:

(2x + 2y)(x - y) + (2x - 2y)(x+y)
= 2(x+y)(x-y) + 2(x-y)(x+y)
= 2(x^2 - y^2) + 2(x^2 - y^2)
= (2 + 2)(x^2 - y^2) (combine like terms)
= 4(x^2 - y^2)

8 0

3 years ago