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klemol [59]
4 years ago
7

Select the correct answer from each drop-down menu. In the figure, line segment AB is parallel to line segment CD. The measure o

f angle C is degrees, and the measure of angles D is degrees.

Mathematics
1 answer:
victus00 [196]4 years ago
3 0
<h3>Answer:</h3>

∠C = 40°

∠D = 75°

<h3>Step-by-step explanation:</h3>

AB ║ CD, so AD and BC are transversals. The angle pairs (A, D) and (B, C) are "alternate interior angles", hence congruent.

∠C = ∠B = 40°

∠D = ∠A = 75°

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A tortoise is walking in the desert. It walks for 4.8 meters at a speed of 3 meters per minute. For how many minutes does it wal
kirill [66]
It is normally smart to write out a diagram of some sort to help you visualize the situation. I made one for this situation, although it might now suit you as well as it would me. 

The idea behind this problem is to make you understand rates. Rates being the same thing as a slope. If you have learned about that already then that will help a lot, but if you haven't then that's fine. 

So we have 4.8m and we traveled at a speed of 3 meters per 1 minute. A rate you are probably pretty familiar with is mph. Which is Miles per Hour. Or if you don't live in the U.S. Kmph. Which is Kilometers per Hour. 

What you do to solve these type of problems is you take the given value and you use the rate to get the value you want.

The easiest way to do this is to make sure the signs (Meters) "cancel" out.  

4.8m * (1min / 3m) 

To cancel something out you need to have it over itself. Here are a few examples: 

3/3 = 1
4/4 = 1 
100,000/100,000 = 1
598/598 = 1

In the case of units, such as meters. They go *poof* from the problem. 
So we have this problem: 
(4.8m*1 minute) / 3m = ? minutes

4.8/3 = 1.6


If you want the answer in fractional form... here is how you do it: (I won't explain it because you most likely won't need to do this, but if you want to know how to do it then just ask)

4(8/10) 
4(4/5)
(24/5)/3 
(24/5) * (1/3) 

24/15
8/5 is our final fractional answer!

5 0
4 years ago
Jane has ​$1 and 9 quarters in her pile. Brody has 13 quarters in his pile. If Jane gives Brody ​$1 and Brody gives Jane 4 quart
lord [1]

Answer:

Yes it will still be equal bc Brody has $3.1 and jane gave brody 1 more dollar then brody gave jane 4 quarters which is 1 dollar that's how the piles will still  be the same

Step-by-step explanation:

plz mark brainilist

6 0
3 years ago
Phil received a prize of xxx dollars from a poker tournament. The tournament cost him 100100100 dollars to enter.
nikitadnepr [17]

Answer:

$(x-100)

Step-by-step explanation:

  • Phil entered the poker tournament with $100.
  • He received a price of $x.

His net winnings from the tournament will be the price minus the entry fee.

Therefore:

Phil's net winnings=$(x-100)

8 0
4 years ago
A large pool of adults earning their first driver’s license includes 50% low-risk drivers, 30% moderate-risk drivers, and 20% hi
Mamont248 [21]

Answer:

The probability that these four will contain at least two more high-risk drivers than low-risk drivers is 0.0488.

Step-by-step explanation:

Denote the different kinds of drivers as follows:

L = low-risk drivers

M = moderate-risk drivers

H = high-risk drivers

The information provided is:

P (L) = 0.50

P (M) = 0.30

P (H) = 0.20

Now, it given that the insurance company writes four new policies for adults earning their first driver’s license.

The combination of 4 new drivers that satisfy the condition that there are at least two more high-risk drivers than low-risk drivers is:

S = {HHHH, HHHL, HHHM, HHMM}

Compute the probability of the combination {HHHH} as follows:

P (HHHH) = [P (H)]⁴

                = [0.20]⁴

                = 0.0016

Compute the probability of the combination {HHHL} as follows:

P (HHHL) = {4\choose 1} × [P (H)]³ × P (L)

               = 4 × (0.20)³ × 0.50

               = 0.016

Compute the probability of the combination {HHHM} as follows:

P (HHHL) = {4\choose 1} × [P (H)]³ × P (M)

               = 4 × (0.20)³ × 0.30

               = 0.0096

Compute the probability of the combination {HHMM} as follows:

P (HHMM) = {4\choose 2} × [P (H)]² × [P (M)]²

                 = 6 × (0.20)² × (0.30)²

                 = 0.0216

Then the probability that these four will contain at least two more high-risk drivers than low-risk drivers is:

P (at least two more H than L) = P (HHHH) + P (HHHL) + P (HHHM)

                                                            + P (HHMM)

                                                  = 0.0016 + 0.016 + 0.0096 + 0.0216

                                                  = 0.0488

Thus, the probability that these four will contain at least two more high-risk drivers than low-risk drivers is 0.0488.

6 0
4 years ago
I need help with this question please ASAP before tomorrow!<br><br> Thank you :)
luda_lava [24]
23- right handed females
7 0
3 years ago
Read 2 more answers
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