Answer:
<h2>2/5</h2>
Step-by-step explanation:
The question is not correctly outlined, here is the correct question
<em>"Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are mathematics majors, and 12 are neither. a student is selected at random from the class. (a) what is the probability that the student is both a junior and a mathematics majors?"</em>
Given data
Total students in class= 35 students
Suppose M is the set of juniors and N is the set of mathematics majors. There are 35 students in all, but 12 of them don't belong to either set, so
|M ∪ N|= 35-12= 23
|M∩N|= |M|+N- |MUN|= 17+20-23
=37-23=14
So the probability that a random student is both a junior and social science major is
=P(M∩N)= 14/35
=2/5
Answer:
x=6
Step-by-step explanation:
Hypotenuse is 10 because it is the opposite of the right angle
8^2+x^2=10^2
64+x^2=100
x^2=36
x=6
The answer is 2,925
to get the answer: 26*112=2912 .5 equals half an hour so half the pages
so you add 2912 + 13= 2925
Answer:6a+9
Step-by-step explanation:
You cant combine a number with a variable that doesn’t have a variable
-17 is the correct answer:)
