Answer:
Sample mean =119.42
Median = 92
25% trimmed mean = 102.42
10% trimmed mean = 95.69
Step-by-step explanation:
Data in increasing order :
12 13 20 23 31 35 40 43 48 49 58 62 66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141 147 159 161 168 183 207 249 262 289 323 388 513
Total no. of observations = 50
Sample mean =
=
= 119.42
Median: Since we have even number of observation
Median =
=
= 92
10% Trimmed Mean: We remove 5 values from each side
Trimmed set = 35 40 43 48 49 58 62 66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141 147 159 161 168 183 207 249
Trimmed mean =
=
= 102.42
25% Trimmed Mean: We remove 12 values from each side.
Trimmed set = 66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141
Trimmed mean =
=
= 95.69
Answer:
C
Step-by-step explanation:
Okay so on Saturday there is a 30% sale plus she comes early so +10% and that makes 40% off.
10% of 400=40
multiply by 4 to get 40%, 40*4=40%
40%=160
400-160=240
Hope this helps
Answer:
85.5 minutes
Step-by-step explanation:
The amount of an element that will remain after time t can be expressed as a function of initial amount N0, time t, and half life th as;
Nt = N0 × e^(-λt)
Where;
Decay constant λ = ln(2)/th, substituting into the equation;
Nt = N0 × e^(-ln(2)t/th)
We need to make t the subject of formula;
Nt/N0 = e^(-ln(2)t/th)
ln(Nt/N0) = -ln(2)t/th
t = ln(Nt/N0) ÷ -ln(2)/th
Given;
Initial amount N0 = 760g
Final amount Nt = 11 g
Half life th = 14 minutes
the nearest tenth of a minute, would it take the element to decay to 11 grams can be derived using the formula;
t = ln(Nt/N0) ÷ -ln(2)/th
Substituting the given values;
t = ln(11/760) ÷ -ln(2)/14
t = 85.5 minutes