All categories

3 years ago

Please help with this

Mathematics

1 answer:

GalinKa [24]3 years ago

7 0

The answer is 20

Reason: so the W is 4 and the L is 6 so you do 4+4=8 then you do 6+6=12 then you add the two together and get 20

You might be interested in

Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar

horsena [70]

Answer:

$P(A) = \frac{1}{9}$

$P(B) = \frac{1}{3}$

$P(C) = \frac{1}{729}$

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

$P(M) = \frac{1}{3}$ .

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

$P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}$

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is $P(A) = \frac{1}{9}$ . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

$P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}$ .

C. If the probability that two people have been hired on a specific day of the week is $3(\frac{1}{3}) ^ 2$ , then the probability that 7 people have been hired on the same day is:

$P(C) = (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7\\\\P(C) = \frac{1}{729}$

D. The probability is $\frac{1}{729}$ . This number is quite close to zero. Therefore it is an unlikely bastate event.

6 0

3 years ago

Constructed Response

Len [333]

Answer:

Check Explanation.

Step-by-step explanation:

Totally, Terrell has 4 protein/meat options and 3 sauce options to pick from.

Meat Options: beef, pork, chicken, or tofu.

Sauce Options: hot, tangy and sweet sauce.

Individually, he could just pick each of the options, but now, the sample space would involve a combination of a protein option and a sauce option. So, the total sample spaces available would be every choice of protein and sauce available.

Using the fundamental counting principle,

A choice of beef meat will be followed by choice of either hot, tangy and sweet sauce giving a sample space of

(beef, hot), (beef, tangy), (beef, sweet)

This can then be repeated across the meat choices

(pork, hot), (pork, tangy), (pork, sweet)

(chicken, hot), (chicken, tangy), (chicken, sweet)

(tofu, hot), (tofu, tangy), (tofu, sweet)

Bringing the total sample spaces to

(beef, hot), (beef, tangy), (beef, sweet), (pork, hot), (pork, tangy), (pork, sweet), (chicken, hot), (chicken, tangy), (chicken, sweet), (tofu, hot), (tofu, tangy) and (tofu, sweet)

Making a total of 12 sample spaces!

Hope this Helps!!!

6 0

3 years ago

Write 106,000,000 in scientific notation

coldgirl [10]

Oh that's easy it is 106 times 10^6

3 0

3 years ago

Read 2 more answers

What is the area of the parallelogram shown?

rodikova [14]

Answer:

Area = 96 square m

Step-by-step explanation:

$Area = base \times height = 12 \times 8 = 96 \ m^2$

6 0

3 years ago

Read 2 more answers

Enter the values for the highlighted variables that show how to subtract the rational expressions correctly:

sladkih [1.3K]

The highlighted variables a = 6 , b = 2, c=6 , d =2 , e=6 , f =6 , g =1

<h3>What is an Expression ?</h3>

An expression is a mathematical statement which consists of variables , constants and mathematical operators.

$\rm \dfrac{2}{x^2-36}-\dfrac{1}{x^2+36}\\= \dfrac{2}{(x+6)(x-6)}-\dfrac{1}{x(x+a)}\\=\dfrac{bx}{x(x+6)(x-6)}-\dfrac{x-c}{x(x+6)(x-6)}\\\\=\dfrac{dx-x+e}{x(x+6)(x-6)}\\\\= \dfrac{x+f}{x(x+6)(x-6)}\\\\=\dfrac{g}{x(x-6)}$

In the given expression

a = 6 , b = 2, c=6 , d =2 , e=6 , f =6 , g =1

To know more about Expression

brainly.com/question/14083225

#SPJ1

8 0

2 years ago