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Arada [10]
3 years ago
14

If R is (-4,7) and S is (-2, 12), what is the component form of the vector RS?

Mathematics
1 answer:
serg [7]3 years ago
5 0

Answer: (-6,19)

Step-by-step explanation:

Add -4 and -2

then add both y1 and y2

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Need this quick!!!
Leya [2.2K]

A function assigns the values. The correct option is graph X.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

The function which is giving a constant term is the graph on the right, while the function where the value of x increases to positive infinity is the upper graph.

Hence, the correct option is graph X.

Learn more about Function:

brainly.com/question/5245372

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7 0
2 years ago
I need assistance solving these questions using Cramers' Rule (which I am frankly terrible at) and need these to finish my homew
Scrat [10]

Answer:

What are the questions?

3 0
3 years ago
Read 2 more answers
Write multiplication expression to represent the change in temperature after the plane ascends 10,000 feet .... Above it says th
Allisa [31]

Answer:

1.3°F * 10 = 13°F

10.2°F

Step-by-step explanation:

Given that:

Temperature on the ground = - 2.8°F

Change in temperature per 1000 ft rise = 1.3°F

Change in temperature after the plane ascends 10000 ft

Change in temperature per 1000ft rise * (10000/1000)

1.3°F * 10 = 13°F

B.) Temperature at 10,000 feets

Temperature on ground + change in temperature at 10,000ft

-2.8°F + 13°F

= 10.2°F

5 0
3 years ago
Please help!
laila [671]
Because
\frac{f(x)}{x-3} = 2x^{2} + 10x - 1
therefore
f(x) = (x-3)(2x² + 10x - 1) + k, where k =  constant.

Because f(3) = 4, therefore k =4.
The polynomial is
f(x) = 2x³ + 10x² - x - 6x² - 30x + 3 + 4
      = 2x³ + 4x² - 31x + 7

Answer:  f(x) = 2x³ + 4x² - 31x + 7

6 0
3 years ago
Match each expression in the left column with the correct product in the right column.
lesya692 [45]

Answer:

-6

-6i

6i

6

Step-by-step explanation:

1) √4 . √-3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2 $

$ \sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 = $ -6

2) √-4 . √-3 . √-3

$ \sqrt{-4} = 2i $ .

Therefore, $ \sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1}  \times -3 = 2i \times (-3) =  $ - 6i

3) √4 . √3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1} $

$ \implies 2 \times 3i = $ 6i

4) √4 . √3 . √3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{3} = (\sqrt{3})^2  = 3 $

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0
3 years ago
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