John drove 255 miles using 10 gallons of gas. At this rate, how many gallons of gas would he need to drive 411 miles?
1 answer:
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Solution
g(x) = 2 - 11x
Plugging in x = -1 in g(x), we get
g(-1) = 2 - 11(-1)
Now we have to simplify it.
g(-1) = 2*1 + 11
g(-1) = 2 + 11
g(-1) = 13
So the answer is D) 13.
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