Question

Q # 1 solve the problem

Answer 1

The solution is shown in the graph attached.

Explanation:

I am goind to teach you how to get that solution.

1) Restricctions: both x and y cannot be negative, i.e. x ≥ 0 and y ≥ 0

⇒ the solution is on the first quadrant.

2) Using the prices of the tickets, $ 8 for adults, and $ 6 for children, the linear equation for the costs is: cost = 8x + 6y.

3) Since the radio station is willing to spend a maximum of $ 172 you have the final restriction:

⇒ 8x + 6y ≤ 172.

4) Then the solutions that meet the three restrictions (x ≥0, y ≥ 0, and 8x + 6y ≤ 172) is found graphically by drawing the line 8 x + 6y = 172

5) To draw the line 8x + 6y = 172, use the axis intercepts:

x = 0 ⇒ y = 172/6 = 86/3 ⇒ point (0, 86/3)

y = 0 ⇒ x = 172/8 = 86/4 ⇒ point (86/4, 0)

6) Once you have the line you shade the region that is between the line and the two axis. That region contain of the possible solutions.

Answer 2

 For this case we have the following variables:
  x = the number of adult tickets
  y = the number of children's tickets
  We write the inequality:
  8x + 6y <= 172
  The solution is the set of points that belong to the region shaded in the graph.
  Answer: 
  8x + 6y <= 172 
  see attached image.