Ask question

Ask question

All categories

3 years ago

8

For which of the following equations is (-2,-3)not a solution? Select one: a. −3x=4y−6 −3x=4y−6 b. y=x−1 y=x−1 c. 5x+2y=−16 5x+2

y=−16 d. 2y−3x=0 2y−3x=0

1 answer:

Misha Larkins [42]3 years ago

4 0

(-2,-3)

It is just a matter of subbing ur points into the equation to see if it is true.

not a solution :
-3x = 4y - 6

You might be interested in

What is the function of delta sign in maths

gladu [14]

The uppercase delta Δ means "change in" so for example: Δx = difference between two x values.

The lowercase delta which Brainly does not have, looks like a squiggly lowercase d. It generally means "very small change in".

7 0

2 years ago

Olk-onm <br> Find the value of u.

damaskus [11]

Answer:

olk 69 -_-

Step-by-step explanation:

5 0

3 years ago

Jessica borrow $316 for 9 months he paid it off by paying $38.27 monthly what will she pay in finance charges

liraira [26]

Answer:

my answer is 34 r 18 I am guessing

6 0

2 years ago

Read 2 more answers

Helpppppppppppppppppp

irina [24]

Option D:

$\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)=8 y^{4}+25 y^{3}+60 y^{2}+10y+7$

Solution:

Given expression is $\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)$ .

<u>To find the product of the expression:</u>

$\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)$

Multiply each term of the first term with each term of the 2nd term.

$=y^{2}\left(8 y^{2}+y+1\right) +3 y\left(8 y^{2}+y+1\right) +7\left(8 y^{2}+y+1\right)$

Using the exponent rule: $a^m \cdot a^n = a^{m+n}$

$=\left(8 y^{4}+y^3+y^2\right) +\left(24 y^{3}+3y^2+3y\right) +\left(56 y^{2}+7y+7\right)$

$=8 y^{4}+y^3+y^2+24 y^{3}+3y^2+3y+56 y^{2}+7y+7$

Arrange the terms with same power.

$=8 y^{4}+y^3+24 y^{3}+y^2+3y^2+56 y^{2}+7y+3y+7$

$=8 y^{4}+25 y^{3}+60 y^{2}+10y+7$

Hence option D is the correct answer.

$\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)=8 y^{4}+25 y^{3}+60 y^{2}+10y+7$

6 0

3 years ago

There are 30 students in Mr.Thomas' class.If he wants 20% of the students in each group, how many students will be in. each grou

zhuklara [117]

First you find out what 20% of 30 is (30 * 0.20 = 6)
Then you take 30/6 to get your answer (30/6 = 5)
There will be 5 students in each group.

8 0

3 years ago

Read 2 more answers