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Rina8888 [55]
3 years ago
14

Is 1.32 a rational number or integer

Mathematics
1 answer:
Ivahew [28]3 years ago
6 0

Answer:

A rational number.

Step-by-step explanation

A rational number is a ratio of whole numbers.

1/3 is the ratio of 1:3

3:1 becomes 3/1 = 3

32:10 can be written 32/10 or 16/5 or 3.2

16/5 is a rational number 16 and 5 are integers, 5 is not equal to 0.

Therefore, 3.2 which can be expressed as 16/5 is a rational number.

You might be interested in
Which system of equations can be used to solve for the point of intersection of the lines on the graph? A) y = x - 7; y = 2x + 2
ratelena [41]

Answer:

C) y = 2x + 7; y = 2x + 2

Step-by-step explanation:

The two lines are parallel and so will have the same slope.

From the graph, the slope of both lines are two.

Using slope intercept formula, y=mx+c, with m=2, we have y=2x+c

The blue line has a y-intercept of 2 so the equation is

y = 2x + 2

The red line has a y-intercept of -7 so the equation is

y = 2x - 7

Hence the system is

y=2x+2

y=2x-7

The correct answer is C

4 0
3 years ago
4. Solve using elimination.<br> 4x -3y = 9<br> 3x +2y = 11
UNO [17]
Answer: (3,1)

Explanation:
8 0
3 years ago
Read 2 more answers
HELP ‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️WILL MARK BRAINLYEST‼️‼️‼️
Rainbow [258]

Answer:

8 one-dollar bills

3 five-dollar bills

2 ten-dollar bills

Step-by-step explanation:

Let x = # of one-dollar bills, y = # of five-dollar bills, and z = # of ten-dollar bills. Total amount in the wallet is $43, so the first equation would be 1x + 5y + 10z = 43. Next, there are 4 times as many one-dollar bills as ten-dollar bills, so x = 4z. There are 13 bills in total, so x + y + z = 13

x + 5y + 10z = 43

x = 4z

x + y + z = 13

x + 5y + 10z = 43

x + 0y - 4z = 0

x + y + z = 13

5y + 14z = 43

-y - 5z = -13

5y + 14z = 43

-5y - 25z = -65

-11z = -22

z = 2

x = 4z

x = 4*2 = 8

x + y + z = 13

8 + y + 2 = 13

10 + y = 13

y = 3

3 0
1 year ago
The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is regi
yan [13]

Answer:

We conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

Step-by-step explanation:

We are given that 513 employed persons and 604 unemployed persons are independently and randomly selected, and that 287 of the employed persons and 280 of the unemployed persons have registered to vote.

Let p_1 = <u><em>percentage of employed workers who have registered to vote.</em></u>

p_2 = <u><em>percentage of unemployed workers who have registered to vote.</em></u>

So, Null Hypothesis, H_0 : p_1\leq p_2      {means that the percentage of employed workers who have registered to vote does not exceeds the percentage of unemployed workers who have registered to vote}

Alternate Hypothesis, H_A : p_1>p_2     {means that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote}

The test statistics that would be used here <u>Two-sample z test for proportions;</u>

                          T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~ N(0,1)

where, \hat p_1 = sample proportion of employed workers who have registered to vote = \frac{287}{513} = 0.56

\hat p_2 = sample proportion of unemployed workers who have registered to vote = \frac{280}{604} = 0.46

n_1 = sample of employed persons = 513

n_2 = sample of unemployed persons = 604

So, <u><em>the test statistics</em></u>  =  \frac{(0.56-0.46)-(0)}{\sqrt{\frac{0.56(1-0.56)}{513}+\frac{0.46(1-0.46)}{604} } }

                                       =  3.349

The value of z test statistics is 3.349.

<u>Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.</u>

Since our test statistic is more than the critical value of z as 3.349 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

5 0
3 years ago
Please explain your answer.
guapka [62]
I think that the answer would be B beacuse both of them are negitive
8 0
3 years ago
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