The lines that are the directrices of the ellipse is B. x = −3.25 and x = 9.25.
<h3>How to calculate the ellipse? </h3>
From the information given, the equation of parabola will be:
= (x - 3)²/5² + (y - 2)²/3² = 1
Hence, h = 3, k = 2, a = 5, b = 3
e = ✓1 - ✓3²/5²
E = 4/5 = 0.8
The directix will be:
x = 3 + 5/0.8
x = 9.25
x = 3 - 5/0.8
x = -3.25
Therefore, lines that are the directrices of the ellipse is x = −3.25 and x = 9.25.
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Y + 0.4 = 2 .....subtract 0.4 from both sides
y = 2 - 0.4
y = 1.6 <==
f(x) = 1 - ²/ₓ₃
y = 1 - ²/ₓ₃
y = 1 - ²/ₓ₃
y - 1 = ⁻²/ₓ₃
x - 1 = -2/y³
y³(x - 1) = -2
y³ = ⁻²/ₓ₋₁
y = ∛⁻²/ₓ₋₁
y = -∛(2x² - 4x + 2)/x - 1
f⁻¹(x) = -∛(2x² - 4x + 2)/x - 1
Answer:
Step-by-step explanation:
Use the Pythagorean theorem. 
a and b are the two side lengths
c is the hypotenuse (value across from the right angle)
Plug in the values that you are given.
Solve for x
x=
