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3 years ago

Solve for x. Round all answers to the nearest tenth

Mathematics

1 answer:

marshall27 [118]3 years ago

7 0

Answer: 42

Step-by-step explanation:

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Raphael paid $167 for a camera during a 75% off sale. what was the cameras regular price?

mihalych1998 [28]

As the camera was at 25% of the original price, this means you've got to multiply this number to by 4 to get the original price.
167*4= 668
Therefore, the camera's regular price is $668
Hope this helps :)

6 0

3 years ago

Read 2 more answers

Write as a single power of 6<br> (6^5)^4

babunello [35]

Answer:

6^20

Step-by-step explanation:

When two indices are in brackets, you just have to multiply them.

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3 years ago

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Lisa [10]

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2 years ago

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N76 [4]

Cool I guess hehehehehe

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3 years ago

Find the following integral

ololo11 [35]

There's nothing preventing us from computing one integral at a time:

$\displaystyle \int_0^{2-x} xyz \,\mathrm dz = \frac12xyz^2\bigg|_{z=0}^{z=2-x} \\\\ = \frac12xy(2-x)^2$

$\displaystyle \int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy = \frac12\int_0^{1-x}xy(2-x)^2\,\mathrm dy \\\\ = \frac14xy^2(2-x)^2\bigg|_{y=0}^{y=1-x} \\\\= \frac14x(1-x)^2(2-x)^2$

$\displaystyle\int_0^1\int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy\,\mathrm dx = \frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx$

Expand the integrand completely:

$x(1-x)^2(2-x)^2 = x^5-6x^4+13x^3-12x^2+4x$

Then

$\displaystyle\frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx = \left(\frac16x^6-\frac65x^5+\frac{13}4x^4-4x^3+2x^2\right)\bigg|_{x=0}^{x=1} \\\\ = \boxed{\frac{13}{240}}$

4 0

2 years ago