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2 years ago

Solve for x. Round all answers to the nearest tenth

Mathematics

1 answer:

marshall27 [118]2 years ago

7 0

Answer: 42

Step-by-step explanation:

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A 40 N force is applied to an object with a mass of 0.1 kg on a frictionless surface. What is the acceleration of the object?

tino4ka555 [31]

Answer:

400

Step-by-step explanation:

40 divided by .1

4 0

3 years ago

What is the value of x? 27(x+4)=−6

jonny [76]

First you need to use the distributive property: 27(x+4)=-6
27x+108=-6
then you need to subtract 108 from -6 to
get x alone. 27x= 102

Lastly divide 102 by 27 to finally get x alone: x=3.777

the answer would be: x= 3.77 or 3.8

5 0

3 years ago

Whats two-thirds of four-fifths of a dozen

leonid [27]

Answer:

Step-by-step explanation:

2/3*4/5*12 =
32/5 =
6.4

6 0

2 years ago

Read 2 more answers

Find e^cos(2+3i) as a complex number expressed in Cartesian form.

ozzi

Answer:

The complex number $e^{\cos(2+31)} = \exp(\cos(2+3i))$ has Cartesian form

$\exp\left(\cosh 3\cos 2\right)\cos(\sinh 3\sin 2)-i\exp\left(\cosh 3\cos 2\right)\sin(\sinh 3\sin 2)$ .

Step-by-step explanation:

First, we need to recall the definition of $\cos z$ when $z$ is a complex number:

$\cos z = \cos(x+iy) = \frac{e^{iz}+e^{-iz}}{2}$ .

Then,

$\cos(2+3i) = \frac{e^{i(2+31)} + e^{-i(2+31)}}{2} = \frac{e^{2i-3}+e^{-2i+3}}{2}$ . (I)

Now, recall the definition of the complex exponential:

$e^{z}=e^{x+iy} = e^x(\cos y +i\sin y)$ .

So,

$e^{2i-3} = e^{-3}(\cos 2+i\sin 2)$

$e^{-2i+3} = e^{3}(\cos 2-i\sin 2)$ (we use that $\sin(-y)=-\sin y)$ .

Thus,

$e^{2i-3}+e^{-2i+3} = e^{-3}\cos 2+ie^{-3}\sin 2 + e^{3}\cos 2-ie^{3}\sin 2)$

Now we group conveniently in the above expression:

$e^{2i-3}+e^{-2i+3} = (e^{-3}+e^{3})\cos 2 + i(e^{-3}-e^{3})\sin 2$ .

Now, substituting this equality in (I) we get

$\cos(2+3i) = \frac{e^{-3}+e^{3}}{2}\cos 2 -i\frac{e^{3}-e^{-3}}{2}\sin 2 = \cosh 3\cos 2-i\sinh 3\sin 2$ .

Thus,

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)$

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right]$ .

5 0

2 years ago

On a certain hot summers day , 293 people used the public swimming pool. Daily prices are $1.50 for children and $2.50 for adult

fredd [130]

C = children

A = adults

293 = c + a

1.50c + 2.50a = 676.50

We can use substitution to solve:

c + a = 293 subtract a to get c = 293 - a

Plug this into the second equation:

1.50(293 - a) + 2.50a = 676.50

439.5 - 1.50a + 2.50a = 676.50

439.5 + 1a = 676.50

a = 237

Substitute this into the first equation:

293 = c + 237

56 = c

8 0

3 years ago