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suter [353]
3 years ago
7

Raphael paid $167 for a camera during a 75% off sale. what was the cameras regular price?

Mathematics
2 answers:
mihalych1998 [28]3 years ago
6 0
As the camera was at 25% of the original price, this means you've got to multiply this number to by 4 to get the original price.
167*4= 668
Therefore, the camera's regular price is $668
Hope this helps :) 
Contact [7]3 years ago
5 0
The original price of the camera was $292.25. I changed 75 percent to a decimal which became 0.75. Then I added $167 plus 0.75 which equals 292.25. When the dollar sign was added, $292.25 was the camera's original price. 

Hope I helped! :)
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Find the area of the geometric figure.<br> Square<br> 9.8 ft
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3 years ago
A certain jet can reach an altitude of 8000 ft while flying 16000 ft through the air. what is the angle of the elevation that th
irina1246 [14]

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27 degrees

Step-by-step explanation:

First, we can draw this out. Since the altitude is 8000, we can make that the height, and it goes 16000 feet through the air, that can be the length. I have drawn this out, as shown in the image. Note that when drawing, because the airplane is going up and forward, that path should represent the hypotenuse. The angle of elevation is the angle connecting the length and the path, as shown by the angle x in the picture.

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4 0
3 years ago
What’s the answer?and how do you get it
Kay [80]

the solid is made up of 2 regular octagons, 8 sides, joined up by 8 rectangles, one on each side towards the other octagonal face.

from the figure, we can see that the apothem is 5 for the octagons, and since each side is 3 cm long, the perimeter of one octagon is 3*8 = 24.

the standing up sides are simply rectangles of 8x3.

if we can just get the area of all those ten figures, and sum them up, that'd be the area of the solid.

\bf \textit{area of a regular polygon}\\\\ A=\cfrac{1}{2}ap~~ \begin{cases} a=apothem\\ p=perimeter\\[-0.5em] \hrulefill\\ a=5\\ p=24 \end{cases}\implies A=\cfrac{1}{2}(5)(24)\implies \stackrel{\textit{just for one octagon}}{A=60} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{two octagon's area}}{2(60)}~~+~~\stackrel{\textit{eight rectangle's area}}{8(3\cdot 8)}\implies 120+192\implies 312

7 0
3 years ago
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