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3 years ago

Raphael paid $167 for a camera during a 75% off sale. what was the cameras regular price?

2 answers:

mihalych1998 [28]3 years ago

6 0

As the camera was at 25% of the original price, this means you've got to multiply this number to by 4 to get the original price.
167*4= 668
Therefore, the camera's regular price is $668
Hope this helps :)

Contact [7]3 years ago

5 0

The original price of the camera was $292.25. I changed 75 percent to a decimal which became 0.75. Then I added $167 plus 0.75 which equals 292.25. When the dollar sign was added, $292.25 was the camera's original price.

Hope I helped! :)

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1 year ago

Compare the scores: a score of 75 on a test with a mean of 65 and a standard deviation of 8 and a score of 75 on a test with a m

LiRa [457]

Answer:

The Zscore for both test is the same

Step-by-step explanation:

Given that :

TEST 1:

score (x) = 75

Mean (m) = 65

Standard deviation (s) = 8

TEST 2:

score (x) = 75

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Standard deviation (s) = 4

USING the relation to obtain the standardized score :

Zscore = (x - m) / s

TEST 1:

Zscore = (75 - 65) / 8

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TEST 2:

Zscore = (75 - 70) / 4

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The standardized score for both test is the same.

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2 years ago

Simplify -6x(9-12) ??

olga55 [171]

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3 years ago

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DerKrebs [107]

Answer:

$\huge\boxed{\left\{-\dfrac{5+\sqrt{21}}{2};\ \dfrac{-5+\sqrt{21}}{2}\right\}}$

Step-by-step explanation:

$x^2+5x+1=0\\\\\text{Use the quadratic formula:}\\\\\text{For}\ ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\\text{if}\ \Delta < 0,\ \text{then the equation has no real solution}\\\text{if}\ \Delta=0,\ \text{then the equation has one real solution}\ x=\dfrac{-b}{2a}\\\text{if}\ \Delta>0,\ \text{then the equation has two real solution}\ x=\dfrac{-b\pm\sqrt{\Delta}}{2a}$

$\text{We have}\\\\a=1,\ b=5,\ c=1\\\\\Delta=5^2-4(1)(1)=25-4=21>0\\\\x=\dfrac{-5\pm\sqrt{21}}{2(1)}=\dfrac{-5\pm\sqrt{21}}{2}$

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3 years ago

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allsm [11]

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3 years ago

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