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Otrada [13]
3 years ago
8

What body system contains a structure that can expand to hold more waste products A. Urinary System B. Endocrine System C. Respi

ratory System
Biology
2 answers:
miv72 [106K]3 years ago
3 0

Answer:

A. Urinary system its the one system that holds waste

Explanation:

jolli1 [7]3 years ago
3 0
A is the right answer
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Maria wakes up in the morning and takes a shower, drinks a glass of water, washes her clothes in the laundry machine, and then g
Ivan

The correct option is this: MARIA'S WATER USE IS CONSUMPTIVE.

Water use can be consumptive or non consumptive. Consumptive water use refers to the process of using water in such a way that the water used can not be returned to the water resources system.

The water that Maria used to shower, the one she drank and the one she used to wash her laundry are waste water, which are not returned to the central water resources system, thus, Maria's water use is consumptive.

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Wich factor drives surface ocean currents wind energy solar energy
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WIND ENERGY drives surface ocean currents
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CAN SOMEONE PLEASEEEE HELP ME WITH THIS SCIENCE QUESTION I WILL MARK YOU BRAINLIEST !!!
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Subsistence agriculture

Explanation:

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2 years ago
Which best defines matter?
Pani-rosa [81]

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A. Anything that takes up space and has mass

Explanation:

Hope this helps!

4 0
2 years ago
The bacterium Neisseria gonorrhoeae, which is responsible for the disease gonorrhea, has a diameter of 0.5 μm. Assuming a spheri
Nezavi [6.7K]

Answer:

SA:V of the bacterium to that of the amoeba = 300

Explanation:

Surface area (SA) of a sphere = 4\pi r^2

Volume (V) of a sphere = \frac{4}{3} \pi r^3

Surface area to volume ratio is equal to

\frac{SA}{V} = \frac{4\pi r^2}{\frac{4}{3} \pi r^3} \\\frac{SA}{V} =\frac{3}{r}

a) For bacteria of diameter = 0.5μm = 0.5 * 0.001 = 0.0005mm

(\frac{SA}{V} )_1= \frac{3}{r} \\(\frac{SA}{V} )_1=\frac{3}{0.0005} \\

= 6000

This means there is 6000 unit surface area per unit volume.

b) For amoeba with a diameter of 150 μm= 150 * 0.001 = 0.15mm

(\frac{SA}{V} )_2= \frac{3}{r} \\(\frac{SA}{V} )_2=\frac{3}{0.15} \\

= 20

The ratio for SA:V of the bacterium to that of the amoeba

= \frac{6000}{20} \\= 300

4 0
3 years ago
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