1. The rectangular prism is a right prism with rectangular bases (check the picture)
2. It has 8 vertices, so we are looking for 3d figures with 4 vertices.
3. A face can have at least 3 vertices, and the 4th must be outside of the plane determined by the first 3 vertices. This makes 4 vertices in total.
4. The 3d figure described in step 3 is a pyramid.
To find the amount of fabric for one side of the purse you will find the area of the trapezoidal space that is created. The latch is on the top, so the 2 in is not necessary information.
A = 1/2 h(b1 + b2)
1/2 x 13 x (10 + 16)
A = 169 square inches of fabric will be needed.
−
4
x
+
7
=
2
Step 1: Subtract 7 from both sides.
−
4
x
+
7
−
7
=
2
−
7
−
4
x
=
−
5
Step 2: Divide both sides by -4.
−
4
x
−
4
=
−
5
−
4
x
=
5
4
The answer is an equilateral triangle
Answer:
35/4, or 8 3/4 as a mixed number
Step-by-step explanation:
First, change 58 1/3 into an improper fraction by multiplying the whole number and denominator, then adding the numerator. 58 x 3 equals 174, + 1 equals 175. So, 58 1/3 as an improper fraction is 175/3. Next, change 6 2/3 into an improper fraction. 6 times 3 equals 18, plus 2 equals 20. So, it's 20/3. So, here are your two fractions:
175/3 & 20/3
To divide fractions, I like to use a method called Keep Change Flip. Basically, you keep the first fractions the same, then change the sign. The division sign changes into a multiplication symbol. Now, your equation should look like this: 175/3 x 20/3. Next, flip the fraction from 20/3 into 3/20. This is what your equation should look like now: 175/3 x 3/20. Now you can multiply the fractions together. Before you do so, you can cross reduce to make it easier. What is a number that both 3 and 3 can be divided by? The correct answer is 3. 3/3= 1, so the equation is now 175/1 x 1/20. However, you can continue to cross reduce. You can also divide 175 and 20 by 5, so the equation changes into this: 35/1 x 1/20. Multiply numerator by numerator, denominator by denominator. So, the answer is 35/4, or 8 3/4 as a mixed number. Hope this helped!
