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8090 [49]
3 years ago
13

A sequence can be generated by using an=12an−1, where n is a whole number greater than or equal to 1.

Mathematics
1 answer:
frutty [35]3 years ago
7 0

Answer:

8, 11, 14, 17

Step-by-step explanation:

For example,

Given: an=2an−1−xan=2an−1−x

a5=99a5=99

a3=27a3=27

a5=2a4−x=2(2a3−x)−x=4a3−3x=99a5=2a4−x=2(2a3−x)−x=4a3−3x=99

4(27)−3x=994(27)−3x=993x=108−99=93x=108−99=9

x=3x=3

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WORTH 80 POINTS HELP
vekshin1
Hi!

1. Your answer should be the first option. (It looks the best to me)

2. it is the last option because it's the only one that's identical to the original picture.

3. It should be the third option since there are 10cm on the top of the shape.

4. a total of 39

Hope that helps, good luck! :)
6 0
3 years ago
Read 2 more answers
Select ALL the correct answers.
stiv31 [10]

Answer:

Statements 3, 4 and 5 are true.

Step-by-step explanation:

x^2 - 8x + 4

Using the quadratic formula:

x = [ -(-8) +/- √((-8)^2 - 4*1*4)] / 2

= (8 +/- √(64 - 16)) / 2

= 4 +/- √48 / 2

= 4 +/- 4√3/2

= 4 +/- 2√3.

So the third statement is true.

Converting to vertex form:

x^2 - 8x + 4

= (x - 4)^2 - 16 + 4

= (x - 4)^2 -12

So the extreme value is at (4, -12)

So the fourth statement is true.

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4 0
3 years ago
Four students each contribute $12 to buy a pizza, salad, and large soda. How much would each student pay if two more students al
geniusboy [140]

Answer:

8$

Step-by-step explanation:

4 students contribute 12$ Each.

So, total amount becomes 12 x 4 = 48$

If two more students contribute it makes a total of 6 students.
so we now divide the 48$ by 6
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8 0
2 years ago
The mean of 10 values is 19. If further 5 values are
Leokris [45]

Answer:

22

Step-by-step explanation:

Pretend the 10 values in the first sentence are a,b,c,d,e,f,g,h,i,j

Pretend the addition 5 values is k,l,m,n,o

So the mean of all the 15 data is (a+b+c+d+e+f+g+h+i+j+k+l+m+n+o)/15=20

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Now let's look at the first 10:  We have their mean so we can write:

(a+b+c+d+e+f+g+h+i+j)/10=19

so a+b+c+d+e+f+g+h+i+j=190                               since 10(19)=190

So that means using our first sum equation and our equation sum equation we have

190+k+l+m+n+o=300

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      k+l+m+n+o= 110

So the average of those 5 numbers mentioned in your problem is 110/5=22

3 0
3 years ago
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Answer: 0.03

Step-by-step explanation:

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