A sequence can be generated by using an=12an−1, where n is a whole number greater than or equal to 1.

Mathematics

1 answer:

frutty [35]3 years ago

7 0

Answer:

8, 11, 14, 17

Step-by-step explanation:

For example,

Given: an=2an−1−xan=2an−1−x

a5=99a5=99

a3=27a3=27

a5=2a4−x=2(2a3−x)−x=4a3−3x=99a5=2a4−x=2(2a3−x)−x=4a3−3x=99

4(27)−3x=994(27)−3x=993x=108−99=93x=108−99=9

x=3x=3

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Someone please help me on these 2 problems!

Veronika [31]

1) function 2) not a function

the first one is a function because its y values are the same number (3), which means it is a horizontal line and horizontal lines are functions.

the second one is not a function because the coordinates cannot have different inputs but different outputs. each input must have only one output.

the coordinates for the second one are:

(2,5); (1,1); (1,2); (3,2)

and <u>a function cannot have two same x-coordinates</u>. it must pass the vertical line test which is a way to tell if something is a function or not. since the second graph does not pass the vertical line test, it is not a function

hope this helps :)

5 0

3 years ago

George is given two circles, circle O and circle X 1 as shown. If he wants to prove that the two circles are similar, what would

salantis [7]

Answer:

Step-by-step explanation:

Given: The radius of circle O is r, and the radius of circle X is r'.

To prove: Circle O is similar to circle X.

Proof: Move the center of the smaller circle onto the center of the largest circle. Translate the circle X by the vector XA onto circle O. The circles now have the same center.

A dilation is needed to increase the size of circle X to coincide with the circle O. A value which when multiplied by r' will create r.

The scale factor x to increase X:

⇒

A translation followed by a dilation with scale factor will map one circle to the other, thus proving the given both circles similar.

Therefore, circle O is similar to circle X.

Step-by-step explanation: