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Temka [501]
3 years ago
12

If you roll a dice 600 times, on how many occasions would you expect to land on a 6

Mathematics
2 answers:
egoroff_w [7]3 years ago
5 0

Answer:

100

Step-by-step explanation:

A dice has 6 sides and, theoretically, each side has the same probability of being rolled. So, if a dice was rolled a number of times, it would land on each side the same number of times. This means that 6 would be rolled 1/6 of the time. Since 1/6 of 600 is 100, that is how many times 6 would be rolled.

zaharov [31]3 years ago
3 0
Answer: 100

a dice has 6 sides. and with 600 rolls, it gives you a 1/6 chance of getting 6. 1/6 of the 600 times you role the dice is 100. Therefore you would expect to land on a 6 200 times.
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jake made some tarts. He sold 3/5 of them and gave 1/4 of the remainder to his friends. If he had 150 tarts left, how many did h
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4 years ago
Use the expression below to complete the following tasks. (3a2 - 5ab + b2) - (-3a2 + 2b2 + 8ab) What is the additive inverse of
Basile [38]
Remember that the additive inverse are two equal numbers (or expressions) but with different signs.
 We have then, that according with the coment below:
 (3a2 - 5ab + b2) - (-3a2 + 2b2 + 8ab)
 the additive inverse is:
 (3a2 - 2b2 - 8ab) Note that is the same expression that
 (-3a2 + 2b2 + 8ab)
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6 0
3 years ago
Read 2 more answers
Mathematics 13 don’t understand
UNO [17]

Answer:

  1/6^3

Step-by-step explanation:

The applicable rules of exponents are ...

  a^-b = 1/a^b

  (a^b)(a^c) = a^(b+c)

__

Your expression can be simplified as follows:

  \dfrac{6^{-5}}{6^{-2}}=\dfrac{1}{(6^{-2})(6^5)}=\dfrac{1}{6^{-2+5}}=\boxed{\dfrac{1}{6^3}}

_____

<em>Additional comment</em>

If you think of an exponent as signifying repeated multiplication, the rules of exponents may be easier to remember. The exponent tells you how many times the base is a factor in the product.

Consider multiplication:

  (x\cdot x\cdot x)\cdot(x\cdot x)=x^3\cdot x^2=x^{3+2}=x^5\\\\(x\cdot x\cdot x)\cdot(x\cdot x\cdot x)=(x^3)^2=x^{3\cdot2}=x^6

Consider division:

  \dfrac{x\cdot x\cdot x}{x\cdot x}=x\quad\Longleftrightarrow\quad\dfrac{x^3}{x^2}=x^{3-2}=x^1\\\\\dfrac{x\cdot x}{x\cdot x\cdot x}=\dfrac{1}{x}\quad\Longleftrightarrow\quad\dfrac{x^2}{x^3}=x^{2-3}=x^{-1}

This may help you see that a positive exponent in the denominator is equivalent to a negative exponent in the numerator (and vice versa).

6 0
3 years ago
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