Find the discriminant of the quadratic equation and indicate the number of roots: (3x^2)+2x+1=0
1 answer:
Answer:
This expression has no roots.
Step-by-step explanation:
Using the discriminant: b² - 4ac, we get:
2² - 4 × 3 × 1
= 4 - 12
= -8
So this equation has no real solutions. Let's prove that by trying to solve for x:
3x² + 2x + 1 = 0
9x² + 6x + 3 = 0
9x² + 6x + 1 = -2
(3x + 1)² = -2
3x + 1 = i√2
3x = -1 ± i√2
x = (-1 ± i√2) / 3
The only solutions available then are indeed complex.
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Simplified the answer is -9x^2 + 12xy
S≤12 s is equal to or less than 12 because 20 minus 12 equals 8. The class will still be held. Any number less than 12, there will be more students than 8 and the class will still be held.
Answer:
7x-5 = 9
x = 2
Step-by-step explanation:
Let x be the number
7x-5 = 9
Add 5 to each side
7x-5+5 = 9+5
Divide each side by 7
7x = 14
7x/7 = 14/7
x=2
Answer:
476 and the top box is 5
Step-by-step explanation:
68×7
Multiply 68 and 7 to get 476.
476
