One of my students got 95 and 98 for the two Principal tests and for the final test. What is the average of her three tests? Wha
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34% of the scores lie between 433 and 523.
Solution:
Given data:
Mean (μ) = 433
Standard deviation (σ) = 90
<u>Empirical rule to determine the percent:</u>
(1) About 68% of all the values lie within 1 standard deviation of the mean.
(2) About 95% of all the values lie within 2 standard deviations of the mean.
(3) About 99.7% of all the values lie within 3 standard deviations of the mean.
Z lies between o and 1.
P(433 < x < 523) = P(0 < Z < 1)
μ = 433 and μ + σ = 433 + 90 = 523
Using empirical rule, about 68% of all the values lie within 1 standard deviation of the mean.
i. e.
Here μ to μ + σ =
Hence 34% of the scores lie between 433 and 523.
This is the answer :
100%-20%=80%
the answer $160
100%-20%=80%
the answer $160
Let the set of all Odd multiples of 9 between 2 and 82 be denoted by D, then, using set-builder notation,
The odd multiples of 9, , in the range
form the set
Each member of the set is a term of the arithmetic progression
where the values of range from 0 to 4, or
Putting these facts together, we get the result
Learn more about set-builder notation here: brainly.com/question/17238769